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If |z(1)|=|z(2)| and arg (z(1))+"arg"(z(...

If `|z_(1)|=|z_(2)|` and arg `(z_(1))+"arg"(z_(2))=0`, then

A

`z_(1) = z_(2)`

B

` z_(1) = bar(z)_(2)`

C

`z_(1) z_(2) = 1 `

D

none

Text Solution

Verified by Experts

The correct Answer is:
B
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