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If z=x+iy and omega=(1-iz)/(z-i), then |...

If `z=x+iy` and `omega=(1-iz)/(z-i)`, then `|omega|=1` implies that in the complex plane

A

z lies on the imaginary axis

B

z lies on the real axis

C

z lies on the axis

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
B
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