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The vector z = - 4 + 5 i is turned count...

The vector z = - 4 + 5 i is turned counterclockwise through an angle of ` 180^(@)` and stretched ` 1 (1)/(2)` times. The complex number corresponding to newly obtained vector is

A

`6 - (15)/(2)i`

B

`- 6 + (15)/(2) i`

C

`6 + (15)/(2)i`

D

none of these

Text Solution

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The correct Answer is:
To solve the problem, we need to perform two operations on the complex number \( z = -4 + 5i \): rotating it counterclockwise by \( 180^\circ \) and then stretching it by a factor of \( \frac{3}{2} \). ### Step-by-Step Solution: 1. **Identify the complex number**: \[ z = -4 + 5i \] 2. **Rotate the complex number by \( 180^\circ \)**: - To rotate a complex number by \( 180^\circ \), we can multiply it by \( -1 \) (which is equivalent to multiplying by \( e^{i\pi} \)). \[ z' = z \cdot (-1) = (-4 + 5i) \cdot (-1) = 4 - 5i \] 3. **Stretch the vector by a factor of \( \frac{3}{2} \)**: - To stretch the complex number, we multiply it by \( \frac{3}{2} \). \[ z'' = z' \cdot \frac{3}{2} = (4 - 5i) \cdot \frac{3}{2} = \frac{3}{2} \cdot 4 - \frac{3}{2} \cdot 5i = 6 - \frac{15}{2}i \] 4. **Final Result**: - The newly obtained complex number after rotation and stretching is: \[ z'' = 6 - \frac{15}{2}i \] ### Conclusion: The complex number corresponding to the newly obtained vector is \( 6 - \frac{15}{2}i \). ---
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