Home
Class 12
MATHS
The number log(20)3 lies in...

The number `log_(20)3` lies in

A

`((1)/(4),(1)/(3))`

B

`((1)/(3),(1)/(2))`

C

`((1)/(2),(3)/(4))`

D

`((3)/(4),(4)/(5))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the value of \( \log_{20} 3 \), we can use the change of base formula for logarithms, which states: \[ \log_a b = \frac{\log_c b}{\log_c a} \] where \( c \) can be any positive number. In this case, we will use base 10 for our calculations. ### Step-by-Step Solution: 1. **Apply the Change of Base Formula**: \[ \log_{20} 3 = \frac{\log_{10} 3}{\log_{10} 20} \] 2. **Calculate \( \log_{10} 20 \)**: We can express \( 20 \) as \( 2 \times 10 \). Using the property of logarithms that states \( \log(ab) = \log a + \log b \), we have: \[ \log_{10} 20 = \log_{10} (2 \times 10) = \log_{10} 2 + \log_{10} 10 \] Since \( \log_{10} 10 = 1 \), we can write: \[ \log_{10} 20 = \log_{10} 2 + 1 \] 3. **Use Known Values**: We can use approximate values for the logarithms: - \( \log_{10} 2 \approx 0.3010 \) - \( \log_{10} 3 \approx 0.4771 \) Thus, we can substitute: \[ \log_{10} 20 \approx 0.3010 + 1 = 1.3010 \] 4. **Substitute Values into the Formula**: Now we can substitute the values back into our equation: \[ \log_{20} 3 = \frac{\log_{10} 3}{\log_{10} 20} = \frac{0.4771}{1.3010} \] 5. **Calculate the Final Value**: Performing the division: \[ \log_{20} 3 \approx \frac{0.4771}{1.3010} \approx 0.3661 \] 6. **Determine the Range**: Since \( 0.3661 \) is between \( 0 \) and \( 1 \), we conclude that: \[ \log_{20} 3 \text{ lies in the interval } (0, 1) \]
Promotional Banner

Topper's Solved these Questions

  • LOGARITHMS AND SURDS

    ML KHANNA|Exercise Problem Set (1) (True and False)|11 Videos
  • LOGARITHMS AND SURDS

    ML KHANNA|Exercise Problem Set (1) (Fill in the blanks)|9 Videos
  • LINEAR PROGRAMMING

    ML KHANNA|Exercise Self Assessment Test|8 Videos
  • MATHEMATICAL REASONING

    ML KHANNA|Exercise PROBLEM SET (2) ASSERTION/REASON|3 Videos

Similar Questions

Explore conceptually related problems

The value of log_(10)3 lies in the interval

The value of log_(30)5 lies in the interval

The value of log_(35)3 lies between ______.

The number N = 6 log_(10) 2+ log_(10) 31 lies between two successive integers whose sum is equal to

The value of log_(40)5 lies between ______.

The number N=2^(log_(2)3log_(3)4*log_(4)5.......log_(99)100) simplifies to

The number of integers in the domain of f(x)=sqrt(log_(2)(log_(3)(log_((1)/(4))x))) is

If log2=0.301 and log3=0.477, find the number of integers in 6^(20)

The number of digits in 20^(301) (given log_(10) 2 = 0.3010 ) is