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If (loga)/(b-c)=(logb)/(c-a)=(logc)/(a-b...

If `(loga)/(b-c)=(logb)/(c-a)=(logc)/(a-b)` then `a^(a).b^(b).c^(c)` =

A

`1`

B

`2`

C

`-1`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
A
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