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If omega!=1 is a cube root of unity and ...

If `omega!=1` is a cube root of unity and
`Delta=|(x+omega^(2),omega,1),(omega,omega^(2),1+x),(1,x+omega,omega^(2))|=0` then value of x is

A

x = 0

B

x = 1

C

x = 2

D

x = - 1

Text Solution

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The correct Answer is:
A
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