Home
Class 12
MATHS
P and Q are points on the line joining A...

P and Q are points on the line joining A(-2,5) and B(3,1) such that AP=PQ=QB. Then the mid pont of PQ is

A

`(1/2,3)`

B

`(-1/2,4)`

C

`(2,3)`

D

`(1,4)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the midpoint of points P and Q on the line segment joining A(-2, 5) and B(3, 1) such that AP = PQ = QB, we can follow these steps: ### Step 1: Determine the Coordinates of Points A and B We have: - A = (-2, 5) - B = (3, 1) ### Step 2: Calculate the Distance AB To find the distance between points A and B, we can use the distance formula: \[ AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2} \] Substituting the coordinates of A and B: \[ AB = \sqrt{(3 - (-2))^2 + (1 - 5)^2} = \sqrt{(3 + 2)^2 + (1 - 5)^2} = \sqrt{5^2 + (-4)^2} = \sqrt{25 + 16} = \sqrt{41} \] ### Step 3: Determine the Length of AP, PQ, and QB Since AP = PQ = QB, we can denote the length of each segment as \(d\). Since the total length AB is divided into three equal parts: \[ AP + PQ + QB = AB \implies 3d = \sqrt{41} \implies d = \frac{\sqrt{41}}{3} \] ### Step 4: Find the Coordinates of Point P Point P divides the segment AB in the ratio 1:2. We can use the section formula: \[ P\left(\frac{mx_2 + nx_1}{m+n}, \frac{my_2 + ny_1}{m+n}\right) \] where \(m = 1\), \(n = 2\), \(A(-2, 5)\) and \(B(3, 1)\): \[ P\left(\frac{1 \cdot 3 + 2 \cdot (-2)}{1 + 2}, \frac{1 \cdot 1 + 2 \cdot 5}{1 + 2}\right) = P\left(\frac{3 - 4}{3}, \frac{1 + 10}{3}\right) = P\left(\frac{-1}{3}, \frac{11}{3}\right) \] ### Step 5: Find the Coordinates of Point Q Point Q divides the segment AB in the ratio 2:1. Again using the section formula: \[ Q\left(\frac{2 \cdot 3 + 1 \cdot (-2)}{2 + 1}, \frac{2 \cdot 1 + 1 \cdot 5}{2 + 1}\right) = Q\left(\frac{6 - 2}{3}, \frac{2 + 5}{3}\right) = Q\left(\frac{4}{3}, \frac{7}{3}\right) \] ### Step 6: Find the Midpoint of PQ The midpoint R of segment PQ can be found using the midpoint formula: \[ R\left(\frac{x_1 + x_2}{2}, \frac{y_1 + y_2}{2}\right) \] Substituting the coordinates of P and Q: \[ R\left(\frac{\frac{-1}{3} + \frac{4}{3}}{2}, \frac{\frac{11}{3} + \frac{7}{3}}{2}\right) = R\left(\frac{3/3}{2}, \frac{18/3}{2}\right) = R\left(\frac{1}{2}, 3\right) \] ### Final Answer The midpoint of PQ is \(\left(\frac{1}{2}, 3\right)\).
Promotional Banner

Topper's Solved these Questions

  • RECTANGULAR CARTESIAN CO-ORDINATE SYSTEM AND THE STRAIGHT LINE

    ML KHANNA|Exercise PROBLEM SET(2)(TRUE AND FALSE)|7 Videos
  • RECTANGULAR CARTESIAN CO-ORDINATE SYSTEM AND THE STRAIGHT LINE

    ML KHANNA|Exercise PROBLEM SET(2)(fill in the blanks)|2 Videos
  • RECTANGULAR CARTESIAN CO-ORDINATE SYSTEM AND THE STRAIGHT LINE

    ML KHANNA|Exercise PROBLEM SET(1)(FILL IN THE BLANK)|3 Videos
  • PROPERTIES OF TRIANGLES

    ML KHANNA|Exercise Self Assessment Test (Multiple Choise Questions)|34 Videos
  • SELF ASSESSMENT TEST

    ML KHANNA|Exercise OBJECTIVE MATHEMATICS |16 Videos

Similar Questions

Explore conceptually related problems

[ A-10.P and Q are points on the line goining A(-2,5) and B(3,1) such that AP=PQ=QB .Then the mid point of PQ .[ (1) ((1)/(2),3), (2) (-(1)/(2),4), (3) (2,3), (4) (1,4)]]

Let P and Q be points on the line joining A(-2, 5) and B(3, 1) such that AP = PQ = QB. If mid-point of PQ is (a, b), then the value of (b)/(a) is

Let P and Q be the points on the line joining A(-2, 5) and B(3, 1) such that AP = PQ=QB . Then, the mid-point of PQ is

P and Q are points on the line joining A(-2,5) and B(3,1) such that AP=PQ=QB .Then,the distance of the midpoint of PQ from the origin is (a) 3(b)(sqrt(37))/(2) (b) 4 (d) 3.5

If P and Q are two points on the line joining A(-2,5),B(3,1) such that AP=PQ=QB then PB=

If A and B are two points on the line joining P (2,5) and Q (4,-7) such that PA =AB=BQ then the mid point of seg AB is

If P and Q are two points on the line joining A(-2,5),B(3,1) such that AP=PQ=QB then PB= sqrt(41) (2sqrt(41))/(3) (sqrt(41))/(3) (4sqrt(41))/(3)

The coordinates of the points A and B are, respectively, (-3, 2) and (2, 3). P and Q are points on the line joining A and B such that AP = PQ = QB. A square PQRS is constructed on PQ as one side, the coordinates of R can be

Two points P and Q are taken on the line joining the points A(0.0) and B(3a,0) such that AP=PQ=QB .Circles are drawn on AP,PQ and QB as diameters.The locus of the point S from which,the sum ofsquares of the lengths of the tangents to the three circles is equal to b^(2) is

ML KHANNA-RECTANGULAR CARTESIAN CO-ORDINATE SYSTEM AND THE STRAIGHT LINE-PROBLEM SET(2)(MULTIPLE CHOICE QUESTIONS)
  1. The line segment joining the points (1,2) and (-2,1) is divided by the...

    Text Solution

    |

  2. If A and B are the points (-3,4) and (2,1). Then the co -ordinates of ...

    Text Solution

    |

  3. P and Q are points on the line joining A(-2,5) and B(3,1) such that AP...

    Text Solution

    |

  4. A the equation of the lines joining the origin to the points of trisec...

    Text Solution

    |

  5. The perpendicular bisector of the line segment joining P (1, 4) and...

    Text Solution

    |

  6. If a straight line passes through (x(1),y(1)) and its segment between ...

    Text Solution

    |

  7. The equations of the straight line passing through the point (4,3) and...

    Text Solution

    |

  8. A straight line through the point P(3,4) is such that its intercept be...

    Text Solution

    |

  9. The equation of the straight line passing through the origin and the m...

    Text Solution

    |

  10. Given points A(4,5),B(-1,-4),C(1,3),D(5,-3),then the ratio of the segm...

    Text Solution

    |

  11. A,B,C are three collinear points such that AB=2.5 and the co ordinate...

    Text Solution

    |

  12. Determine the ratio in which the line y - x + 2 = 0 divides the line...

    Text Solution

    |

  13. Consider three points P=(-sin (beta-alpha),-cos beta), Q=(cos (beta-a...

    Text Solution

    |

  14. If the lines 3y+4x=1, y=x+5 and 5y+bx=3 are concurrent then the value ...

    Text Solution

    |

  15. Three lines px+qy+r=0, qx+ry+p=0 and rx+py+q=0 are concurrent , if

    Text Solution

    |

  16. a,b,c are the sides of a triangle ABC. If the lines ax+by+c=0,bx+cy+a=...

    Text Solution

    |

  17. The lines x+ay+a^(3)=0, x+by+b^(3)=0 and x+cy+c^(3)=0 where a,b,c are ...

    Text Solution

    |

  18. Given the four lines with the equations x+2y-3=0, 3x+4y-7=0, 2x+3y...

    Text Solution

    |

  19. The three straight lines 2x+11y-5=0, 24x+7y=20 and 4x-3y-2=0 are such ...

    Text Solution

    |

  20. The three lines l(1)=4x-3y+2=0,l(2)=3x+4y-4=0 and l(3)=x-7y+6=0

    Text Solution

    |