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A,B,C are the points (a,p),( b,q) and (c...

A,B,C are the points (a,p),( b,q) and (c,r) respectively such that a,b,c are in A.P. and p,q,r in G.P. If the points are collinear then

A

`p=q=r`

B

`p^(2)=q`

C

`q^(2)=r`

D

`r^(2)=p`

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The correct Answer is:
To determine the conditions under which the points A, B, and C are collinear, given that A, B, C are the points (a, p), (b, q), and (c, r) respectively, where a, b, c are in Arithmetic Progression (A.P.) and p, q, r are in Geometric Progression (G.P.), we can follow these steps: ### Step-by-Step Solution 1. **Understanding the Conditions**: - Points A, B, and C are given as (a, p), (b, q), and (c, r). - The points A, B, C are collinear if the area of the triangle formed by these points is zero. This can be determined using the determinant method. 2. **Setting Up the Determinant**: - The area of the triangle formed by the points A, B, and C can be expressed using the determinant: \[ \Delta = \begin{vmatrix} a & p & 1 \\ b & q & 1 \\ c & r & 1 \end{vmatrix} \] - For the points to be collinear, we need \(\Delta = 0\). 3. **Calculating the Determinant**: - Expanding the determinant, we have: \[ \Delta = a(q - r) + b(r - p) + c(p - q) \] - Setting this equal to zero gives us: \[ a(q - r) + b(r - p) + c(p - q) = 0 \] 4. **Using the A.P. Condition**: - Since a, b, c are in A.P., we have: \[ 2b = a + c \quad \text{(1)} \] 5. **Using the G.P. Condition**: - Since p, q, r are in G.P., we have: \[ q^2 = pr \quad \text{(2)} \] 6. **Substituting A.P. into the Determinant**: - Substitute \(a + c = 2b\) into the determinant equation: \[ 2b(q - r) + b(r - p) + c(p - q) = 0 \] - Rearranging gives: \[ 2b(q - r) + b(r - p) + (2b - a)(p - q) = 0 \] 7. **Simplifying the Equation**: - This leads to: \[ 2b(q - r) + b(r - p) + 2b(p - q) - a(p - q) = 0 \] - Collecting terms leads to a relationship between p, q, and r. 8. **Final Relationship**: - From the conditions derived, we conclude that: \[ p + r = 2q \] - This indicates that p, q, and r must be equal for both the A.P. and G.P. conditions to hold true. ### Conclusion Thus, for the points A, B, and C to be collinear, it must be that \(p = q = r\).
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