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If 3x+4y+3=0,3x+4y-7=0 and 4x-3y-2=0 be ...

If `3x+4y+3=0,3x+4y-7=0` and `4x-3y-2=0` be the three sides of a square, then the equation of the fourth side is

A

`4x-3y-12=0`

B

`4x-3y+8=0`

C

`4x-3y-10=0`

D

`4x-3y+6=0`

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To find the equation of the fourth side of the square given the equations of the three sides, we can follow these steps: ### Step 1: Identify the given lines The equations of the three sides of the square are: 1. \( 3x + 4y + 3 = 0 \) (Line 1) 2. \( 3x + 4y - 7 = 0 \) (Line 2) 3. \( 4x - 3y - 2 = 0 \) (Line 3) ### Step 2: Find the distance between the parallel lines The first two lines are parallel since they have the same coefficients for \(x\) and \(y\). The distance \(d\) between two parallel lines \(Ax + By + C_1 = 0\) and \(Ax + By + C_2 = 0\) is given by the formula: \[ d = \frac{|C_2 - C_1|}{\sqrt{A^2 + B^2}} \] For our lines: - \(C_1 = 3\) (from Line 1) - \(C_2 = -7\) (from Line 2) Calculating the distance: \[ d = \frac{|-7 - 3|}{\sqrt{3^2 + 4^2}} = \frac{|-10|}{\sqrt{9 + 16}} = \frac{10}{5} = 2 \] ### Step 3: Determine the length of the side of the square Since the distance between the two parallel lines is 2, this represents the length of one side of the square. ### Step 4: Find the fourth side of the square The third line \(4x - 3y - 2 = 0\) is not parallel to the first two lines. We need to find the equation of the fourth side of the square, which will also be parallel to the line \(4x - 3y - 2 = 0\). The general form of the equation of a line parallel to \(4x - 3y - 2 = 0\) is: \[ 4x - 3y + C = 0 \] ### Step 5: Calculate the distance from the third line to the fourth side The distance from the line \(4x - 3y - 2 = 0\) to the new line \(4x - 3y + C = 0\) must equal the side length of the square, which is 2. Using the distance formula again: \[ \frac{|C - (-2)|}{\sqrt{4^2 + (-3)^2}} = 2 \] This simplifies to: \[ \frac{|C + 2|}{5} = 2 \] ### Step 6: Solve for \(C\) Multiplying both sides by 5 gives: \[ |C + 2| = 10 \] This results in two cases: 1. \(C + 2 = 10 \Rightarrow C = 8\) 2. \(C + 2 = -10 \Rightarrow C = -12\) ### Step 7: Write the equations of the fourth side Thus, we have two possible equations for the fourth side: 1. \(4x - 3y + 8 = 0\) 2. \(4x - 3y - 12 = 0\) ### Conclusion The equation of the fourth side of the square can be either: 1. \(4x - 3y + 8 = 0\) 2. \(4x - 3y - 12 = 0\)
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ML KHANNA-RECTANGULAR CARTESIAN CO-ORDINATE SYSTEM AND THE STRAIGHT LINE-PROBLEM SET(2)(MULTIPLE CHOICE QUESTIONS)
  1. Consider the equation y-k=m(x-h). In this equation, if m and h are fix...

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  2. If a pair of opposite vertices of parallelogram are (1,3) and (-2,4) ...

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  3. If 3x+4y+3=0,3x+4y-7=0 and 4x-3y-2=0 be the three sides of a square, t...

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  4. The equations to a pair of opposite sides of a parallelogram are x^(2)...

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  5. The point P(a,b) and Q(b,a) lie on the lines 3x+2y-13=0 and 4x-y-5=0. ...

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  6. How are the points (3,4) and (2,-6) situated w.r.t the line 3x-4y-8=0?

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  7. The sides AB,BC,CD and DA of a quadrilateral are x+2y=3,x=1,x-3y=4,5x...

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  8. The equation of the line through the point (-5,4) such that its segmen...

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  9. Let PS be the median of the triangle with vertices P(2,2), Q(6,-1) an ...

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  10. If A(9,-9),B(1,3) are the ends of a right angled isosceles triangle t...

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  11. A triangle ABC right angled at A has points A and B as (2, 3) and (0, ...

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  12. The medians AD and BE of the triangle with vertices A(0,b),B(0,0) and ...

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  13. The line 4x+y=lamda cuts the axes of co ordinates at A and B. If C is ...

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  14. The equations of perpendicular bisectors of the sides AB and AC of a ...

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  15. The side AB of an isosceles triangle is along the axis of x with verti...

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  16. A straight line through the point (2,2) intersects the line sqrt(3)x+y...

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  17. The line ax+by+c=0 intersects the line x cos alpha+y sinalpha=c at the...

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  18. A line passes through (2,2) and is perpendicular to the line 3x+y=3 .I...

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  19. If the lines x(sinalpha+sinbeta)-ysin(alpha-beta)=3 and x(cosalpha+c...

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  20. The lines p(p^2+1)x-y+q=0 and (p^2+1)^2x+(p^2+1)y+2q=0 are perpendicul...

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