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The side AB of an isosceles triangle is ...

The side AB of an isosceles triangle is along the axis of x with vertices `A (–1, 0)` and `AB = AC`. The equation of the side BC when `angleA=120^(@)` and `BC=4sqrt(3)` is:

A

`sqrt(3)x+y=3`

B

`x+y=sqrt(3)`

C

`x+sqrt(3)y=3`

D

None

Text Solution

Verified by Experts

The correct Answer is:
C
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