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The three lines 4x - 7y + 10 , x + y = 5...

The three lines `4x - 7y + 10 , x + y = 5 and 7x+ 4y = 15 ` form the sides of a triangle Then the point (1,2) is its

A

centroid

B

incentre

C

orthocentre

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
C
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The three lines 4x-7y+10=0,x+y=5 and 7x+4y=15 form the sides of a triangle. Then the point (1,2) is its (B) incentre (A) centroid (D) none of these (C) orthocentre

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Knowledge Check

  • The radical centre of three circles described on the three sides 4x - 7y + 10 = 0, x + y - 5 = 0 and 7x + 4y - 15 = 0 of a triangle as diameters is

    A
    `(2,1)`
    B
    `(1,2)`
    C
    `(2,3)`
    D
    `(-6,-2)`

  • If 7x + 6 y = 5xy and 10 x - 4y = 4xy, then value of x and y is

    A
    `3,2`
    B
    `2,3`
    C
    `4,2`
    D
    `5,6`

  • If the equations of three sides of a triangle are x+y=1, 3x + 5y = 2 and x - y = 0 then the orthocentre of the triangle lies on the line/lines

    A
    `5x-3y=1`
    B
    `5y-3x=1`
    C
    `2x-3y=1`
    D
    `5x-3y=2`

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