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The algebraic sum of the perpendicular d...

The algebraic sum of the perpendicular distance from `A(x_(1),y_(1)),B(x_(2),y_(2))` and `C(x_(3),y_(3))` to a variable line is zero, then the line passes through

A

the orthocentre of `DeltaABC`

B

the centroid of `DeltaABC`

C

the circumcentre of `DeltaABC`

D

None of these

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To solve the problem, we need to determine the conditions under which the algebraic sum of the perpendicular distances from points \( A(x_1, y_1) \), \( B(x_2, y_2) \), and \( C(x_3, y_3) \) to a variable line is zero. ### Step-by-Step Solution: 1. **Understanding the Perpendicular Distance**: The perpendicular distance \( d \) from a point \( (x_0, y_0) \) to the line \( Ax + By + C = 0 \) is given by the formula: \[ d = \frac{|Ax_0 + By_0 + C|}{\sqrt{A^2 + B^2}} \] 2. **Setting Up the Equation**: We need to find the sum of the perpendicular distances from points \( A \), \( B \), and \( C \) to the line, which should equal zero: \[ d_A + d_B + d_C = 0 \] Substituting the formula for distance, we have: \[ \frac{|Ax_1 + By_1 + C|}{\sqrt{A^2 + B^2}} + \frac{|Ax_2 + By_2 + C|}{\sqrt{A^2 + B^2}} + \frac{|Ax_3 + By_3 + C|}{\sqrt{A^2 + B^2}} = 0 \] 3. **Simplifying the Expression**: Since \( \sqrt{A^2 + B^2} \) is a positive quantity (it cannot be zero), we can multiply through by \( \sqrt{A^2 + B^2} \) to eliminate the denominator: \[ |Ax_1 + By_1 + C| + |Ax_2 + By_2 + C| + |Ax_3 + By_3 + C| = 0 \] 4. **Analyzing the Absolute Values**: The only way for the sum of absolute values to equal zero is if each individual term is zero: \[ Ax_1 + By_1 + C = 0 \] \[ Ax_2 + By_2 + C = 0 \] \[ Ax_3 + By_3 + C = 0 \] 5. **Conclusion**: If the algebraic sum of the perpendicular distances is zero, then the line must pass through all three points \( A \), \( B \), and \( C \). However, if we consider the centroid of triangle \( ABC \), which is given by: \[ \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right) \] The line will pass through the centroid of triangle \( ABC \). ### Final Answer: The line passes through the centroid of triangle \( ABC \).
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ML KHANNA-RECTANGULAR CARTESIAN CO-ORDINATE SYSTEM AND THE STRAIGHT LINE-PROBLEM SET(4)(MULTIPLE CHOICE QUESTIONS)
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  4. One side of an equilateral triangle is the line 3x+4y+8=0 and its cent...

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  5. The circumcentre of the triangle formed by the lines xy+2x+2y+4=0 and...

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  6. A point equidistant from the line 4x + 3y + 10 = 0, 5x-12y + 26 = 0 an...

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  7. If the orthocentre and centroid of a triangle are (-3, 5) and (3, 3) t...

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  8. Of the three lines x+sqrt(3)y=0,x+y=1 and x-sqrt(3)y=0 two are equatio...

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  9. Vertics of a triangle ABC are the points (0,0),(a,0) and (a/2,(asqrt(3...

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  10. The vertices of a triangle OAB are (0,0),(a,0) and (0,b) respectively...

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  11. The vertices of a triangle are (1,2) (2,1) and {1/2(3+sqrt(3)),1/2(3+s...

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  12. p(1),p(2),p(3) are the distances of points (1,1),(2,0) and (0,2) from ...

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  13. The incentre of triangle with vertices (1, sqrt(3)), (0,0) and (2, 0) ...

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  14. One vertex of the equilateral triangle with centroid at the origin and...

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  15. Two vertices of a triangle ABC are B(5,-1) and C(-2,3) .If the orthoce...

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  16. If one of the diagonals of a square is along the line x=2y and one of ...

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  17. A pair of straight lines drawn through the origin form with the line 2...

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  20. A ray of light coming from the point (1,2) is reflected at a pont A on...

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