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If one of the diagonals of a square is along the line `x=2y` and one of its vertices is (3, 0), then its sides through this vertex are given by the equations (A) `y-3x+9=0, 3y+x-3=0` (B) `y+3x+9=0, 3y+x-3=0` (C) `y-3x+9=0, 3y-x+3=0` (D) `y-3x+9=0, 3y+x+9=0`

A

`y-3x+9=0,3y+x-3=0`

B

`y+3x+9=0,3y+x-3=0`

C

`y-3x+9=0,3y-x+3=0`

D

`y-3x+3=,3y+x=9=0`

Text Solution

Verified by Experts

The correct Answer is:
B
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