Home
Class 12
MATHS
The equation of the bisector of the acut...

The equation of the bisector of the acute angle between the lines
`3x-4y+7=0` and `12x+5y-2=0` is

A

`21x+77y-101=0`

B

`11x+3y+20=0`

C

`21x-7y+3=0`

D

`11x-3y+9=0`

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the bisector of the acute angle between the lines given by the equations \(3x - 4y + 7 = 0\) and \(12x + 5y - 2 = 0\), we can follow these steps: ### Step 1: Rewrite the equations in standard form The equations are already in the standard form \(Ax + By + C = 0\): 1. Line 1: \(3x - 4y + 7 = 0\) (Here, \(A_1 = 3\), \(B_1 = -4\), \(C_1 = 7\)) 2. Line 2: \(12x + 5y - 2 = 0\) (Here, \(A_2 = 12\), \(B_2 = 5\), \(C_2 = -2\)) ### Step 2: Make the constant term of one equation positive To ensure consistency, we can multiply the second equation by -1 to make the constant term positive: \[ - (12x + 5y - 2) = 0 \implies -12x - 5y + 2 = 0 \] ### Step 3: Check the condition for acute angle bisector We need to check if \(A_1A_2 + B_1B_2 < 0\): \[ A_1A_2 + B_1B_2 = 3 \cdot 12 + (-4) \cdot 5 = 36 - 20 = 16 \] Since \(16 > 0\), we will use the positive sign for the acute angle bisector formula. ### Step 4: Use the formula for the angle bisector The formula for the angle bisector between two lines is given by: \[ \frac{A_1x + B_1y + C_1}{\sqrt{A_1^2 + B_1^2}} = \pm \frac{A_2x + B_2y + C_2}{\sqrt{A_2^2 + B_2^2}} \] Substituting the values: \[ \frac{3x - 4y + 7}{\sqrt{3^2 + (-4)^2}} = \frac{12x + 5y - 2}{\sqrt{12^2 + 5^2}} \] Calculating the denominators: \[ \sqrt{3^2 + (-4)^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \] \[ \sqrt{12^2 + 5^2} = \sqrt{144 + 25} = \sqrt{169} = 13 \] ### Step 5: Set up the equation Thus, we have: \[ \frac{3x - 4y + 7}{5} = \frac{12x + 5y - 2}{13} \] ### Step 6: Cross-multiply to eliminate the fractions Cross-multiplying gives: \[ 13(3x - 4y + 7) = 5(12x + 5y - 2) \] ### Step 7: Expand both sides Expanding both sides: \[ 39x - 52y + 91 = 60x + 25y - 10 \] ### Step 8: Rearrange the equation Bringing all terms to one side: \[ 39x - 60x - 52y - 25y + 91 + 10 = 0 \] \[ -21x - 77y + 101 = 0 \] Multiplying through by -1 gives: \[ 21x + 77y - 101 = 0 \] ### Step 9: Simplify the equation To simplify, we can divide by the common factor (if any). However, in this case, we can leave it as is or check for further simplification. ### Final Equation The equation of the acute angle bisector is: \[ 21x + 77y - 101 = 0 \]
Promotional Banner

Topper's Solved these Questions

  • RECTANGULAR CARTESIAN CO-ORDINATE SYSTEM AND THE STRAIGHT LINE

    ML KHANNA|Exercise PROBLEM SET(4)(TRUE AND FALSE)|4 Videos
  • RECTANGULAR CARTESIAN CO-ORDINATE SYSTEM AND THE STRAIGHT LINE

    ML KHANNA|Exercise PROBLEM SET(4)(FILL IN THE BLANKS)|5 Videos
  • RECTANGULAR CARTESIAN CO-ORDINATE SYSTEM AND THE STRAIGHT LINE

    ML KHANNA|Exercise PROBLEM SET(3)(FILL IN THE BLANKS)|7 Videos
  • PROPERTIES OF TRIANGLES

    ML KHANNA|Exercise Self Assessment Test (Multiple Choise Questions)|34 Videos
  • SELF ASSESSMENT TEST

    ML KHANNA|Exercise OBJECTIVE MATHEMATICS |16 Videos

Similar Questions

Explore conceptually related problems

Find the equation of the bisector of the obtuse angle between the lines 3x-4y+7=0 and 12x+5y-2=0

The equation of the bisector of the acute angle between the lines 2x-y+4=0 and x-2y=1 is (a) x-y+5=0 (b) x-y+1=0( c) x-y=5 (d) none of these

The equations of the bisectors of the angles between the straight line 3x-4y+7=0 and 12x-5y-8=0 , are:

The equation of the bisector of the obtuse angle between the lines x-2y+4=0 and 4x-3y+2=0 is

The equation of the bisector of the obtuse angle between the lines x-y+2=0 , 7x+y+1=0 is

ML KHANNA-RECTANGULAR CARTESIAN CO-ORDINATE SYSTEM AND THE STRAIGHT LINE-PROBLEM SET(4)(MULTIPLE CHOICE QUESTIONS)
  1. The equations of the lines through (-1,-1) and making angle 45a with t...

    Text Solution

    |

  2. A ray of light coming from the point (1,2) is reflected at a pont A on...

    Text Solution

    |

  3. Let PQR be a right angled isosceles triangle, right angled at P(2,1). ...

    Text Solution

    |

  4. The equation of the bisector of the acute angle between the lines 3...

    Text Solution

    |

  5. Let P=(-1,0),Q(0,0) and R=(3,3sqrt(3)) be three points. Then the equat...

    Text Solution

    |

  6. Area of Delta formed by line x+y=3 and / bisectors of pair of straight...

    Text Solution

    |

  7. The equation of the line whilch bisects the obtuse angle between the l...

    Text Solution

    |

  8. The vertices of a triangle ABC are (1,1),(4,-2) and (5,5) respectively...

    Text Solution

    |

  9. The vertices of a triangle are A(-1,-7), B(5,1) and C(1,4). The equati...

    Text Solution

    |

  10. The equation(s) of the bisectors(s) of that angles between the lines x...

    Text Solution

    |

  11. The bisector of the acute angle formed between the lines 4x-3y+7=0 and...

    Text Solution

    |

  12. The lines L(1) : y - x = 0 and L(2) : 2x + y = 0 intersect the line ...

    Text Solution

    |

  13. OrthocentreH: It is the point of intersection of altitude of a triangl...

    Text Solution

    |

  14. The line lx+my+n=0 bisects the angle between a pair of straight lines ...

    Text Solution

    |

  15. The vertices of a triangle are A(p,p tan alphat), B(q,qtan beta),C(r,t...

    Text Solution

    |

  16. The vertices of a triangle are [at(1)t(2),a(t(1)+t(2))],[at(2)t(3),a(...

    Text Solution

    |

  17. Prove that the orthocentre of the triangle formed by the three lines ...

    Text Solution

    |

  18. The sides of a triangle are l(R)=xcos alpha(r)+ysin alpha(r)-p(r)=0,...

    Text Solution

    |

  19. Let P=(-1,0),Q=(0,0) and R=(3,3sqrt(3)) be three points. The equation ...

    Text Solution

    |

  20. If one of the lines of my^(2)+(1-m^(2))xy-mx^(2)=0 is a bisector of th...

    Text Solution

    |