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Let P=(-1,0),Q(0,0) and R=(3,3sqrt(3)) b...

Let `P=(-1,0),Q(0,0)` and `R=(3,3sqrt(3))` be three points. Then the equation of the bisector of the angle PQR is

A

`(sqrt(3))/2x+y=0`

B

`x+sqrt(3)y=0`

C

`sqrt(3)x+y=0`

D

`x+(sqrt(3))/2y=0`

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the bisector of the angle PQR formed by the points P=(-1,0), Q=(0,0), and R=(3,3√3), we will follow these steps: ### Step 1: Plot the Points First, we plot the points P, Q, and R on the Cartesian plane: - P = (-1, 0) - Q = (0, 0) - R = (3, 3√3) ### Step 2: Determine the Angles Next, we need to find the angles at point Q formed by the lines PQ and QR. The slopes of these lines will help us determine the angles. 1. **Slope of PQ**: \[ \text{slope of PQ} = \frac{y_2 - y_1}{x_2 - x_1} = \frac{0 - 0}{0 - (-1)} = 0 \] 2. **Slope of QR**: \[ \text{slope of QR} = \frac{3\sqrt{3} - 0}{3 - 0} = \frac{3\sqrt{3}}{3} = \sqrt{3} \] ### Step 3: Find the Angle Between the Lines Using the tangent of the angle between two lines: \[ \tan(\theta) = \left| \frac{m_1 - m_2}{1 + m_1 m_2} \right| \] where \( m_1 = 0 \) (slope of PQ) and \( m_2 = \sqrt{3} \) (slope of QR). Calculating: \[ \tan(\theta) = \left| \frac{0 - \sqrt{3}}{1 + 0 \cdot \sqrt{3}} \right| = \sqrt{3} \] This means that the angle \( \theta \) is \( 60^\circ \) or \( \frac{\pi}{3} \). ### Step 4: Determine the Angle Bisector The angle bisector will split the angle at Q into two equal angles of \( 30^\circ \) each. The slope of the angle bisector can be found using the tangent of \( 30^\circ \): \[ \tan(30^\circ) = \frac{1}{\sqrt{3}}. \] ### Step 5: Equation of the Angle Bisector The slope of the angle bisector is \( -\frac{1}{\sqrt{3}} \) (since it is in the third quadrant). The equation of the line in point-slope form (passing through Q=(0,0)) is: \[ y - 0 = -\frac{1}{\sqrt{3}}(x - 0). \] This simplifies to: \[ y = -\frac{1}{\sqrt{3}}x. \] ### Step 6: Rearranging the Equation To express this in standard form: \[ \sqrt{3}y + x = 0. \] Thus, the equation of the angle bisector of angle PQR is: \[ \sqrt{3}x + y = 0. \] ### Final Answer The equation of the bisector of the angle PQR is: \[ \sqrt{3}x + y = 0. \]
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