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The line x/a+y/b=1 moves in such a way t...

The line `x/a+y/b=1` moves in such a way that `1/(a^(2))+1/(b^(2))=1/(c^(2))` where ic si a constnat. The locus of the foot of perpendicular from the origin on the given line is `x^(2)+y^(2)=c^(2)`

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