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The equation of pair of tangents drawn f...

The equation of pair of tangents drawn from the point (0,1) to the circle `x^(2) + y^(2) – 2x + 4y = 0` is–

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The correct Answer is:
`2x-y+1=0, x+2y-2=0`
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Knowledge Check

  • The equation of tangents drawn from the point (0,1) to the circle x^2+y^2-4x-2y+4=0 are

    A
    2x-y+1=0 ,x+2y-2=0
    B
    2x-y-1=0 ,x+2y-2=0
    C
    2x-y+1=0,x+2y+2=0
    D
    `x=+-sqrt(3)(y-1)`

  • The angle between the pair of tangents drawn from the point (2,4) to the circle x^(2)+y^(2)=4 is

    A
    `tan^(-1)(3//8)`
    B
    `tan^(-1)(4//3)`
    C
    `90^(@)`
    D
    none

  • The equation of the tangent from the point (0,1) to the circle x^2+y^2-2x-6y+6=0 , is

    A
    y-1=0
    B
    4x+3y+3=0
    C
    4x-3y-3=0
    D
    y+1=0

    • Similar Questions

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    The number of tangents that can be drawn from the point (0,1) to the circle x^(2)+y^(2)-2x -4y=0 is

    Find the length of a tangent drawn from the point (3,4) to the circle x ^(2) + y ^(2) - 4x + 6y -3=0.

    The length of the tangent drawn from the point (2, 3) to the circles 2(x^(2) + y^(2)) – 7x + 9y – 11 = 0 .

    Combined equation to the pair of tangents drawn from the origin to the circle x^(2)+y^(2)+4x+6y+9=0 is

    Length of a tangent drawn from the origin to the circle x ^(2) + y ^(2) - 6x + 4y + 8=0 in units is

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