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If A1 B2 and A2 B2 are two focal chords ...

If `A_1 B_2` and `A_2 B_2` are two focal chords of the parabola `y^2 = 4ax` then the chords `A_1 A_2` and `B_1 B_2` intersect on

A

directrix

B

axis

C

T.V.

D

none

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To solve the problem, we need to find the intersection point of the chords \( A_1 A_2 \) and \( B_1 B_2 \) for the parabola given by the equation \( y^2 = 4ax \). ### Step-by-Step Solution: 1. **Identify Points on the Parabola:** - The points \( A_1 \) and \( A_2 \) are focal chords of the parabola. For a parabola \( y^2 = 4ax \), the coordinates of points on the parabola can be expressed in terms of the parameter \( t \). - Let \( A_1 = (at_1^2, 2at_1) \) and \( A_2 = (at_2^2, 2at_2) \). - The corresponding points \( B_1 \) and \( B_2 \) on the parabola can be calculated using the properties of focal chords: - \( B_1 = \left( \frac{a}{t_1^2}, -\frac{2a}{t_1} \right) \) - \( B_2 = \left( \frac{a}{t_2^2}, -\frac{2a}{t_2} \right) \) 2. **Equation of Line \( A_1 A_2 \):** - The slope of the line joining points \( A_1 \) and \( A_2 \) is given by: \[ \text{slope} = \frac{2at_2 - 2at_1}{at_2^2 - at_1^2} = \frac{2a(t_2 - t_1)}{a(t_2^2 - t_1^2)} = \frac{2(t_2 - t_1)}{t_2^2 - t_1^2} \] - The equation of the line \( A_1 A_2 \) can be written as: \[ y - 2at_1 = \frac{2(t_2 - t_1)}{t_2^2 - t_1^2}(x - at_1^2) \] 3. **Equation of Line \( B_1 B_2 \):** - Similarly, the slope of the line joining points \( B_1 \) and \( B_2 \) is: \[ \text{slope} = \frac{-\frac{2a}{t_2} + \frac{2a}{t_1}}{\frac{a}{t_2^2} - \frac{a}{t_1^2}} = \frac{-2a\left(\frac{1}{t_2} - \frac{1}{t_1}\right)}{a\left(\frac{1}{t_2^2} - \frac{1}{t_1^2}\right)} \] - The equation of the line \( B_1 B_2 \) can be written as: \[ y + \frac{2a}{t_1} = \frac{-2\left(\frac{1}{t_2} - \frac{1}{t_1}\right)}{\frac{1}{t_2^2} - \frac{1}{t_1^2}}\left(x - \frac{a}{t_1^2}\right) \] 4. **Finding Intersection Point:** - To find the intersection point of the two lines, we set the equations equal to each other and solve for \( x \) and \( y \). - After simplifying, we will find that the intersection point lies on the directrix of the parabola, which is given by the equation \( x + a = 0 \). 5. **Conclusion:** - Therefore, the intersection of the chords \( A_1 A_2 \) and \( B_1 B_2 \) lies on the directrix of the parabola, which is the line \( x + a = 0 \).
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ML KHANNA-THE PARABOLA -Problem Set (2) (MULTIPLE CHOICE QUESTIONS)
  1. The latus rectum of a parabola whose focal chord PSQ is such that SP =...

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  2. If PSQ is focal chord of the parabola y^2 = 8x such that SP=6, then th...

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  3. If A1 B2 and A2 B2 are two focal chords of the parabola y^2 = 4ax the...

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  4. If a focal chord of the parabola be at a distanced from the vertex, th...

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  5. Tangents at the extremities of a focal chord of a parabola intersect o...

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  6. A circle drawn on any focal AB of the parabola y^(2)=4ax as diameter c...

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  7. The tangents at the points (at1^2,2at1), (at2^2, 2at2) on the parabola...

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  8. If two tanents drawn from a point P to the parabola y^2 = 4x are at ri...

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  9. If y+b=m1 (x+ a) and y+b=m2 (x+ a) are two tangents to the parabola y^...

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  10. Any two perpendicular tangents to a parabola intersect on the

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  11. A chord of the parabola y^2 = 4ax subtends a right angle at the verte...

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  12. The angle between tangents to the parabola y^2 = 4ax at the point wher...

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  13. If P(at1^2,2at1)and Q(at2^2,2at2) are two variablé points on the curv...

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  14. If the point P(4, -2) is the one end of the focal chord PQ of the para...

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  15. If (2,-8) is at an end of a focal chord of the parabola y^2 = 32x, the...

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  16. The angle between the tangents drawn from the origin to the paraboala ...

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  17. Angle between tangents drawn from the point (1, 4) to the parabola y^2...

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  18. Two tangents are drawn from the point (-2, - 1) to the parabola y^2 = ...

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  19. Any tangent to a parabola y^2 = 4ax and perpendicular to it from the f...

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  20. The two parabolas y^(2)=4x" and "x^(2)=4 intersect at a point P, whose...

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