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The line (x-2)/3 = (y-3)/4 = (z-4)/5 is ...

The line `(x-2)/3 = (y-3)/4 = (z-4)/5` is parallel to the plane

A

`2x+y-2z=0`

B

`3x+4y+5z=7`

C

`x+y+z=2`

D

`2x+3y+4z=0`

Text Solution

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The correct Answer is:
A
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The line (x-2)/(3)=(y-3)/(4)=(z-4)/(5) is is parallel to the plane

Find the plane containing the line (x-2)/(2)=(y-3)/(3)=(z-4)/(5) and parallel to the line (x+1)/(1)=(y-1)/(-2)=(-z+1)/(1)

Knowledge Check

  • Distance of point P(-2,3,4) from the line (x+2)/3=(2y+3)/4=(3z+4)/5 measured parallel to the plane 8x+6y-9z+1=0 is

    A
    `(sqrt(301))/2`
    B
    `(sqrt(401))/2`
    C
    `(sqrt(307))/2`
    D
    `(sqrt(207))/2`

  • If the line (x+1)/3=(y-2)/4=(z+6)/5 is parallel to the planes 2x-3y+kz=0 , then the value of k is

    A
    `5/6`
    B
    `6/5`
    C
    `3/4`
    D
    `4/5`

  • The distance of the point (3,8,2) from the line (x-1)/2=(y-3)/4=(z-2)/3 measured parallel to the plane 3x+2y-2z=0 is

    A
    2
    B
    3
    C
    6
    D
    7

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