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Find the vector equation of the plane th...

Find the vector equation of the plane through the points (2,1,-1) and (-1,3,4) and perpendicular to the plane `x-2y+4z=10`.

A

`18x+17y+4z=49`

B

`18x-17y+4z=49`

C

`18x+17y-4z+49=0`

D

None of these

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The correct Answer is:
A
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Find the vector equation of the plane through the points (2, 1, -1) and (-1, 3, 4) and perpendicular to the plane x-y+4z=10.

Find the vector equation of the plane passing through the points (2,1,-1) and (-1,3,4) and perpendicular to the plane x-2y+4z=10. Also show that the plane thus obtained contains the line vec r=-hat i+3hat j+4hat k+lambda(3hat i-2hat j-5hat k)

Knowledge Check

  • The equation of the plane through the points (2,1,-1) and (-1,3,4) and perpendicular to the plane x-2y+4z=10 is

    A
    `18x+17y+4z=49`
    B
    `18x-17y+4z=49`
    C
    `18x-17y-4z=49`
    D
    None of these

  • The equation of the plane which passes through the points (2, 1, -1) and (-1, 3, 4) and perpendicular to the plane x- 2y + 4z = 0 is

    A
    `18x + 17y + 4z = 49`
    B
    `18x - 17y + 4z = 49`
    C
    `18x + 17y - 4z + 49 = 0`
    D
    `18x +17y + 4z -49 = 0`

    • Similar Questions

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    Find the equation of the plane through the points (2,1,1) and (1,3,4) and perpendicular to the plane x-2y+4z=10 .

    Find the equation of the plane through the points A(2,1,-1) and B(-1,3,4) and perpendicular to the plane x-2y+4z=10 . Also, show that the plane thus obtained contains the line vecr=(-hati+3hatj+4hatk)+lambda(3hati-2hatj-5hatk) .

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