Home
Class 12
MATHS
The equation of the plane through the li...

The equation of the plane through the line of intersection of planes `ax+by+cz+d=0,a^(')x+b^(')y+c^(')z+d^(')=0` and parallel to the line `y=0,z=0` is

A

`(ab^(')-a^(')b)x+(bc^(')-b^(')c)y+(ad^(')-a^(')d)=0`

B

`(ab^(')-a^(')b)x+(bc^(')-b^(')c)y+(ad^(')-a^(')d)z=0`

C

`(ab^(')-a^(')b)y+(bc^(')-b^(')c)z+(ad^(')-a^(')d)=0`

D

none of these

Text Solution

AI Generated Solution

The correct Answer is:
To find the equation of the plane through the line of intersection of the planes \( ax + by + cz + d = 0 \) and \( a'x + b'y + c'z + d' = 0 \), and which is parallel to the line \( y = 0 \) and \( z = 0 \), follow these steps: ### Step 1: Understand the Given Planes The two planes are given by: 1. \( E_1: ax + by + cz + d = 0 \) 2. \( E_2: a'x + b'y + c'z + d' = 0 \) ### Step 2: Find the Equation of the Plane Through the Line of Intersection The equation of the plane through the line of intersection of two planes can be expressed as: \[ E_2 + \lambda E_1 = 0 \] This means: \[ a'x + b'y + c'z + d' + \lambda(ax + by + cz + d) = 0 \] Expanding this gives: \[ (a' + \lambda a)x + (b' + \lambda b)y + (c' + \lambda c)z + (d' + \lambda d) = 0 \] ### Step 3: Apply the Condition for Parallelism Since the required plane is parallel to the line \( y = 0 \) and \( z = 0 \), it implies that the plane must be vertical and can be expressed in the form: \[ A x + B = 0 \] This means that the coefficients of \( y \) and \( z \) must be zero: \[ b' + \lambda b = 0 \quad \text{and} \quad c' + \lambda c = 0 \] ### Step 4: Solve for \( \lambda \) From \( b' + \lambda b = 0 \): \[ \lambda = -\frac{b'}{b} \quad (b \neq 0) \] From \( c' + \lambda c = 0 \): \[ \lambda = -\frac{c'}{c} \quad (c \neq 0) \] Equating the two expressions for \( \lambda \): \[ -\frac{b'}{b} = -\frac{c'}{c} \] This gives us the relationship: \[ \frac{b'}{b} = \frac{c'}{c} \] ### Step 5: Substitute \( \lambda \) Back into the Plane Equation Substituting \( \lambda = -\frac{b'}{b} \) into the plane equation: \[ (a' - \frac{b'}{b} a)x + 0 \cdot y + 0 \cdot z + (d' - \frac{b'}{b} d) = 0 \] This simplifies to: \[ (a' - \frac{b'}{b} a)x + (d' - \frac{b'}{b} d) = 0 \] ### Step 6: Final Equation of the Plane The final equation of the required plane can be expressed as: \[ (a' - \frac{b'}{b} a)x + (d' - \frac{b'}{b} d) = 0 \] This is the equation of the plane through the line of intersection of the given planes and parallel to the specified line.
Promotional Banner

Topper's Solved these Questions

  • CO-ORDINATE GEOMETRY OF THREE DIMENSION

    ML KHANNA|Exercise PROBLEM SET (4)|19 Videos
  • CO-ORDINATE GEOMETRY OF THREE DIMENSION

    ML KHANNA|Exercise MISCELLANEOUS EXERCISE(TRUE AND FALSE)|27 Videos
  • CO-ORDINATE GEOMETRY OF THREE DIMENSION

    ML KHANNA|Exercise PROBLEM SET (2)|12 Videos
  • BINOMIAL THEOREM AND MATHEMATICAL INDUCTION

    ML KHANNA|Exercise Self Assessment Test |35 Videos
  • COMPLEX NUMBERS

    ML KHANNA|Exercise Assertion / Reason |2 Videos

Similar Questions

Explore conceptually related problems

The equation of the plane through the line of intersection of the planes ax+by+cz+d=0 and a'x+b'y+c'z+d'=0 parallel to the line y=0 and z=0 is

Find the equation of the plane through the line of intersection of the planes x+2y+3z+2=0 , 2x+3y-z+3=0 and perpendicular to the plane x+y+z=0

The equation of the plane through the intersection of the plane a x+b y+c z+d=0\ a n d\ l x+m y+n+p=0 and parallel to the line y=0,\ z=0. (A) (b l-a m)y+(c l-a n)z+d l-a p=0 (B) (a m-b l)x+(m c-b n)z+m d-b p=0 (c) (n a-c l)d+(b n-c m)y+n d-c p=0 (D) None of these

The equation of the plane passing through the line of intersection of the planes x+y+z=6 and 2x+3y+4z+5=0 and perpendicular to the plane 4x+5y-3z=8 is

The equation of plane through the line of intersection of the planes 2x+3y+4z-7=0,x+y+z-1=0 and perpendicular to the plane x+y+z-1=0

The equation of plane passing through the line of intersection of planes x+y+z-2=0,2x+3y+z-4=0 and parallel to X-axis is

ML KHANNA-CO-ORDINATE GEOMETRY OF THREE DIMENSION-PROBLEM SET (3)
  1. The equation of the plane passing through (2,3,-4) and (1,-1,3) and pa...

    Text Solution

    |

  2. Equation of the line passing through the point (1,2,3) and parellel to...

    Text Solution

    |

  3. The equation of the plane through the line of intersection of planes a...

    Text Solution

    |

  4. The equation of the plane containing the line (x-alpha)/l=(y-beta)/m=(...

    Text Solution

    |

  5. The point at which the line joining the points (2, -3, 1) and (3, -4, ...

    Text Solution

    |

  6. If the line (x-4)/(1)=(y-2)/(1)=(z-k)/(2) lies exactly on the plane 2x...

    Text Solution

    |

  7. Distance of the point of intersection of the line (x-2)/3=(y+1)/4=(z-2...

    Text Solution

    |

  8. The direction cosines of a line equally inclines to three mutually per...

    Text Solution

    |

  9. The equation of a plane through the line of intersection of planes 2x+...

    Text Solution

    |

  10. Two system of rectangular axes have the same origin. If a plane cuts t...

    Text Solution

    |

  11. Distance of the point (1,-2,3) from the plane x-y+z = 5 measured paral...

    Text Solution

    |

  12. The foot of perpendicular drawn from the point (1,3,4) to the plane 2x...

    Text Solution

    |

  13. The image of the point (-1, 3, 4) in the plane x-2y=0 is

    Text Solution

    |

  14. The line (x-2)/(3)=(y+1)/(2)=(z-1)/(-1) intersects the curve xy=c^2, z...

    Text Solution

    |

  15. The coordinates of the foot of the perpendicular drawn from the point ...

    Text Solution

    |

  16. If a x+b y+c z=p , then minimum value of x^2+y^2+z^2 is (p/(a+b+c))^2 ...

    Text Solution

    |

  17. The image of the point A (1,0,0) in the line (x - 1)/(2) = (x + 1)/(-3...

    Text Solution

    |

  18. Find the angle between line (x+1)/3=(y-1)/2=(z-2)/4 and the plane 2x+y...

    Text Solution

    |

  19. P is a fixed point (a,a,a) on a line through the origin equally inclin...

    Text Solution

    |

  20. The length of the perpendicular from P(1,6,3) to the line x/1=(y-1)/(2...

    Text Solution

    |