Home
Class 12
MATHS
The center of the sphere which passes th...

The center of the sphere which passes through `(a,0,0),(0,b,0),(0,0,c) and (0,0,0)` is

A

`(a/2,0,0)`

B

`(0,b/2,0)`

C

`(0,0,c/2)`

D

`(a/2,b/2,c/2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the center of the sphere that passes through the points \( (a, 0, 0) \), \( (0, b, 0) \), \( (0, 0, c) \), and the origin \( (0, 0, 0) \), we can follow these steps: ### Step 1: Define the center of the sphere Let the center of the sphere be denoted as \( H(x, y, z) \). ### Step 2: Set up the distance equations Since the sphere passes through all four points, the distances from the center \( H \) to each of these points must be equal. Therefore, we can set up the following equations based on the distance formula: 1. Distance from \( H \) to the origin \( O(0, 0, 0) \): \[ HO = \sqrt{x^2 + y^2 + z^2} \] 2. Distance from \( H \) to \( A(a, 0, 0) \): \[ HA = \sqrt{(x - a)^2 + y^2 + z^2} \] 3. Distance from \( H \) to \( B(0, b, 0) \): \[ HB = \sqrt{x^2 + (y - b)^2 + z^2} \] 4. Distance from \( H \) to \( C(0, 0, c) \): \[ HC = \sqrt{x^2 + y^2 + (z - c)^2} \] ### Step 3: Equate distances Since all distances are equal, we can set the equations as follows: 1. From \( HO = HA \): \[ \sqrt{x^2 + y^2 + z^2} = \sqrt{(x - a)^2 + y^2 + z^2} \] Squaring both sides gives: \[ x^2 + y^2 + z^2 = (x - a)^2 + y^2 + z^2 \] Simplifying this, we get: \[ x^2 = x^2 - 2ax + a^2 \implies 2ax = a^2 \implies x = \frac{a}{2} \] 2. From \( HO = HB \): \[ \sqrt{x^2 + y^2 + z^2} = \sqrt{x^2 + (y - b)^2 + z^2} \] Squaring both sides gives: \[ x^2 + y^2 + z^2 = x^2 + (y - b)^2 + z^2 \] Simplifying this, we get: \[ y^2 = y^2 - 2by + b^2 \implies 2by = b^2 \implies y = \frac{b}{2} \] 3. From \( HO = HC \): \[ \sqrt{x^2 + y^2 + z^2} = \sqrt{x^2 + y^2 + (z - c)^2} \] Squaring both sides gives: \[ x^2 + y^2 + z^2 = x^2 + y^2 + (z - c)^2 \] Simplifying this, we get: \[ z^2 = z^2 - 2cz + c^2 \implies 2cz = c^2 \implies z = \frac{c}{2} \] ### Step 4: Conclusion Thus, the coordinates of the center \( H \) of the sphere are: \[ H\left(\frac{a}{2}, \frac{b}{2}, \frac{c}{2}\right) \] ### Final Answer The center of the sphere is \( \left(\frac{a}{2}, \frac{b}{2}, \frac{c}{2}\right) \). ---
Promotional Banner

Topper's Solved these Questions

  • CO-ORDINATE GEOMETRY OF THREE DIMENSION

    ML KHANNA|Exercise MISCELLANEOUS EXERCISE(TRUE AND FALSE)|27 Videos
  • CO-ORDINATE GEOMETRY OF THREE DIMENSION

    ML KHANNA|Exercise MISCELLANEOUS EXERCISE( FILL IN THE BLANKS)|16 Videos
  • CO-ORDINATE GEOMETRY OF THREE DIMENSION

    ML KHANNA|Exercise PROBLEM SET (3)|50 Videos
  • BINOMIAL THEOREM AND MATHEMATICAL INDUCTION

    ML KHANNA|Exercise Self Assessment Test |35 Videos
  • COMPLEX NUMBERS

    ML KHANNA|Exercise Assertion / Reason |2 Videos

Similar Questions

Explore conceptually related problems

Assertion:The centre of the sphere which passes through the point (a,0,0),(0,b,0), (0,0,c) and (0,0,0) si (a/2,0,0) Reason: Points on a sphere are equidistant from its centre. (A) Both A and R are true and R is the correct explanation of A (B) Both A and R are true R is not te correct explanation of A (C) A is true but R is false. (D) A is false but R is true.

Find the equation of the sphere which passes through (10,0),(0,1,0) and (0,0,1) and whose centre lies on the plane 3x-y+z=2

Find the equation of the sphere which passes through the point (1,0,0),(0,1,0) and (0,0,1) and has its radius as small as possible.

Find the equation of a sphere which passes through (1,0,0)(0,1,0) and (0,0,1) and has radius as small as possible.

Find the equation of the sphere passing through (0,0,0),(1,0,0),(-,1,0) and (0,0,1)

Find the equation of the sphere passing through (0, 0, 0), (1, 0, 0), (0, 1, 0) and (0, 0, 1) .

The smaller radius of the sphere passing through (1, 0,0),(0,1,0) and (0,0, 1)is:

ML KHANNA-CO-ORDINATE GEOMETRY OF THREE DIMENSION-PROBLEM SET (4)
  1. The equation of the sphere circumscribing the tetrahedron whose faces ...

    Text Solution

    |

  2. If a sphere of constant radius k passes through the origin and meets t...

    Text Solution

    |

  3. The plane x/a+y/b+z/c=1 meets the coordinate axes at A,B and C respect...

    Text Solution

    |

  4. A sphere of constant radius 2k passes through the origin and meets ...

    Text Solution

    |

  5. The center of the sphere which passes through (a,0,0),(0,b,0),(0,0,c) ...

    Text Solution

    |

  6. Find the equation of the sphere which passes through the point (1,0,0)...

    Text Solution

    |

  7. The plane 2x-2y+z+12=0 touches the sphere x^(2)+y^(2)+z^(2)-2x-4y+2z-3...

    Text Solution

    |

  8. The equation of the sphere concentric with the sphere x^(2)+y^(2)+z^(2...

    Text Solution

    |

  9. Equation of the sphere with center (1,-1,1) and radius equal to that o...

    Text Solution

    |

  10. If (2, 3, 5) is one end of a diameter of the sphere x^(2)+y^(2)+z^(2)-...

    Text Solution

    |

  11. If (2, 3, 5) is one end of a diameter of the sphere x^(2)+y^(2)+z^(2)-...

    Text Solution

    |

  12. Find the number of sphere of radius r touching the coordinate ax...

    Text Solution

    |

  13. The radius of the circular section of the sphere x^(2)+y^(2)+z^(2)=25 ...

    Text Solution

    |

  14. The radius of the circle in which the sphere x^(I2)+y^2+z^2+2z-2y-4...

    Text Solution

    |

  15. The center of the circle x^(2)+y^(2)+z^(2)-3x+4y-2z-5=0 and 5x-2y +4...

    Text Solution

    |

  16. The center of a sphere which touches the lines y=x,z=c and y=-x,z=-c l...

    Text Solution

    |

  17. The shortest distance from the plane 12 x+y+3z=327 to the sphere x^...

    Text Solution

    |

  18. The intersection of the spheres x^2+y^2+z^2+7x-2y-z=13a n dx^2+y^2=...

    Text Solution

    |

  19. If the plane 2ax-3ay+4az+6=0 passes through the mid point of the line ...

    Text Solution

    |