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It is given that cos(theta-alpha)=a, c...

It is given that `cos(theta-alpha)=a, cos(theta-beta)=b`
What is `sin^(2)(alpha-beta)+2abcos(alpha-beta)` equal to ?

A

`a^(2) + b^(2)`

B

`a^(2) - b^(2)`

C

`b^(2) - a^(2)`

D

`-a^(2) - b^(2)`

Text Solution

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The correct Answer is:
A
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ML KHANNA-TRIGONOMETRY RATIOS AND IDENTITIES-PROBLEM SET (3) ( MULTIPLE CHOICE QUESTIONS)
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  19. If x sin theta = y sin ( theta + ( 2pi )/( 3)) = z sin( ( theta + 4pi ...

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