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If x sin theta = y sin ( theta + ( 2pi )...

If `x sin theta = y sin ( theta + ( 2pi )/( 3)) = z sin( ( theta + 4pi )/( 3))`, then `Sigma xy =`

A

1

B

`1//2`

C

0

D

none of these

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The correct Answer is:
To solve the equation \( x \sin \theta = y \sin \left( \theta + \frac{2\pi}{3} \right) = z \sin \left( \theta + \frac{4\pi}{3} \right) \) and find \( \Sigma xy \), we will follow these steps: ### Step 1: Set up the equations From the given condition, we can write: 1. \( x \sin \theta = y \sin \left( \theta + \frac{2\pi}{3} \right) \) 2. \( x \sin \theta = z \sin \left( \theta + \frac{4\pi}{3} \right) \) ### Step 2: Express \( y \) in terms of \( x \) From the first equation, we can express \( y \): \[ y = \frac{x \sin \theta}{\sin \left( \theta + \frac{2\pi}{3} \right)} \] ### Step 3: Use the sine addition formula Using the sine addition formula, we have: \[ \sin \left( \theta + \frac{2\pi}{3} \right) = \sin \theta \cos \frac{2\pi}{3} + \cos \theta \sin \frac{2\pi}{3} \] We know: \[ \cos \frac{2\pi}{3} = -\frac{1}{2}, \quad \sin \frac{2\pi}{3} = \frac{\sqrt{3}}{2} \] So, \[ \sin \left( \theta + \frac{2\pi}{3} \right) = \sin \theta \left(-\frac{1}{2}\right) + \cos \theta \left(\frac{\sqrt{3}}{2}\right) \] ### Step 4: Substitute back into the equation for \( y \) Now substituting this back into the equation for \( y \): \[ y = \frac{x \sin \theta}{-\frac{1}{2} \sin \theta + \frac{\sqrt{3}}{2} \cos \theta} \] ### Step 5: Express \( z \) in terms of \( x \) Similarly, from the second equation, we can express \( z \): \[ z = \frac{x \sin \theta}{\sin \left( \theta + \frac{4\pi}{3} \right)} \] Using the sine addition formula again: \[ \sin \left( \theta + \frac{4\pi}{3} \right) = \sin \theta \cos \frac{4\pi}{3} + \cos \theta \sin \frac{4\pi}{3} \] Where: \[ \cos \frac{4\pi}{3} = -\frac{1}{2}, \quad \sin \frac{4\pi}{3} = -\frac{\sqrt{3}}{2} \] So, \[ \sin \left( \theta + \frac{4\pi}{3} \right) = \sin \theta \left(-\frac{1}{2}\right) + \cos \theta \left(-\frac{\sqrt{3}}{2}\right) \] ### Step 6: Substitute back into the equation for \( z \) Now substituting this back into the equation for \( z \): \[ z = \frac{x \sin \theta}{-\frac{1}{2} \sin \theta - \frac{\sqrt{3}}{2} \cos \theta} \] ### Step 7: Form the equations for \( \frac{x}{y} \) and \( \frac{x}{z} \) Now we can form the equations: 1. \( \frac{x}{y} = -\frac{1}{2} + \frac{\sqrt{3}}{2} \cot \theta \) 2. \( \frac{x}{z} = -\frac{1}{2} - \frac{\sqrt{3}}{2} \cot \theta \) ### Step 8: Add the two equations Adding these two equations: \[ \frac{x}{y} + \frac{x}{z} = -1 \] ### Step 9: Rearranging gives us the final equation This leads us to: \[ xz + xy + yz = 0 \] ### Step 10: Conclusion Thus, we find that: \[ \Sigma xy = xy + yz + zx = 0 \] ### Final Answer \[ \Sigma xy = 0 \] ---
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ML KHANNA-TRIGONOMETRY RATIOS AND IDENTITIES-PROBLEM SET (3) ( MULTIPLE CHOICE QUESTIONS)
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  2. If cos e ctheta-sintheta=a^3,sectheta-costheta=b^3, Prove that : a^2b...

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  3. If sin A + cos A = p, sin^(3) A + cos^(3) A=q, then

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  4. If x=sectheta-tantheta, and y=cosectheta+cottheta, then

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  5. If:x/a costheta+y/b s intheta=1a n dx/a s intheta-y/bcostheta=1, Prov...

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  7. If p sec theta - b tan theta =a and q sec theta +a tan theta =b, then

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  8. If a+b tan theta = sec theta and b - a tan theta = 3 sec theta, then ...

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  9. For 0 lt phi le ( pi )/( 2), if x = sum(n=0)^(oo) cos^(2n) phi , y = s...

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  10. If tan x = ( 2b )/( a-c) , ( a cancel(=)c) y = a cos ^(2) x + 2b sin...

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  11. If sin x + cos x = sqrt( 2) cos x , then cos x - sin x is equal to

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  12. If theta is an acute angle and sin"" ( theta )/( 2) = sqrt((x-1)/( 2x)...

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  13. If a cos theta - b sin theta =c, " then" a sin theta + b cos theta is...

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  14. If sin A + sin 2A =x and cos A + cos 2A = y, then ( x^(2) + y^(2) ) ( ...

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  15. It is given that cos(theta-alpha)=a, cos(theta-beta)=b What is...

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  16. If a sin^(2)x+b cos^(2)x=c, b sin^(2)y+a cos^(2)y=d and atan x=btany t...

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  17. If (sin^4x)/2+(cos^4x)/3=1/5t h e n tan^2x=2/3 (b) (sin^8x)/8+(cos^...

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  18. If (x)/(cos theta)=(y)/(cos(theta-(2pi)/(2)))=(2)/(cos(theta+(2pi)/(3)...

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  19. If x sin theta = y sin ( theta + ( 2pi )/( 3)) = z sin( ( theta + 4pi ...

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  20. |{:(cos ( theta +A), sin ( theta +A),1),(cos ( theta +B),sin ( theta +...

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