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sin 78^(@) - sin 66^(@) - sin 42^(@) + s...

`sin 78^(@) - sin 66^(@) - sin 42^(@) + sin 6^(@) =`

A

`-1`

B

`-1//2`

C

`1//2`

D

1

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AI Generated Solution

The correct Answer is:
To solve the expression \( \sin 78^\circ - \sin 66^\circ - \sin 42^\circ + \sin 6^\circ \), we will follow these steps: ### Step 1: Rearranging the Expression We can rearrange the expression as follows: \[ \sin 78^\circ - \sin 42^\circ - \sin 66^\circ + \sin 6^\circ \] ### Step 2: Grouping Terms Next, we will group the terms into pairs: \[ (\sin 78^\circ - \sin 42^\circ) + (\sin 6^\circ - \sin 66^\circ) \] ### Step 3: Applying the Sine Difference Formula We will use the sine difference formula: \[ \sin A - \sin B = 2 \sin\left(\frac{A - B}{2}\right) \cos\left(\frac{A + B}{2}\right) \] #### For the first pair: Let \( A = 78^\circ \) and \( B = 42^\circ \): \[ \sin 78^\circ - \sin 42^\circ = 2 \sin\left(\frac{78^\circ - 42^\circ}{2}\right) \cos\left(\frac{78^\circ + 42^\circ}{2}\right) \] Calculating: \[ = 2 \sin\left(\frac{36^\circ}{2}\right) \cos\left(\frac{120^\circ}{2}\right) = 2 \sin(18^\circ) \cos(60^\circ) \] #### For the second pair: Let \( A = 6^\circ \) and \( B = 66^\circ \): \[ \sin 6^\circ - \sin 66^\circ = 2 \sin\left(\frac{6^\circ - 66^\circ}{2}\right) \cos\left(\frac{6^\circ + 66^\circ}{2}\right) \] Calculating: \[ = 2 \sin\left(\frac{-60^\circ}{2}\right) \cos\left(\frac{72^\circ}{2}\right) = 2 \sin(-30^\circ) \cos(36^\circ) \] ### Step 4: Substituting Known Values Now we substitute the known values: \[ \cos(60^\circ) = \frac{1}{2}, \quad \sin(18^\circ) = \frac{\sqrt{5} - 1}{4}, \quad \sin(-30^\circ) = -\frac{1}{2}, \quad \cos(36^\circ) = \frac{\sqrt{5} + 1}{4} \] ### Step 5: Putting It All Together Now substituting back into the expression: \[ 2 \sin(18^\circ) \cos(60^\circ) + 2 \sin(-30^\circ) \cos(36^\circ) \] This simplifies to: \[ 2 \cdot \frac{\sqrt{5} - 1}{4} \cdot \frac{1}{2} + 2 \cdot \left(-\frac{1}{2}\right) \cdot \frac{\sqrt{5} + 1}{4} \] Calculating each part: \[ = \frac{\sqrt{5} - 1}{4} - \frac{\sqrt{5} + 1}{4} \] Combining the fractions: \[ = \frac{(\sqrt{5} - 1) - (\sqrt{5} + 1)}{4} = \frac{\sqrt{5} - 1 - \sqrt{5} - 1}{4} = \frac{-2}{4} = -\frac{1}{2} \] ### Final Answer Thus, the final answer is: \[ \boxed{-\frac{1}{2}} \]
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ML KHANNA-TRIGONOMETRY RATIOS AND IDENTITIES-PROBLEM SET (4) ( MULTIPLE CHOICE QUESTIONS)
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  2. Find the value of cos 12^(@)+cos 84^(@)+cos 156^(@)+cos 132^(@)

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  3. sin 78^(@) - sin 66^(@) - sin 42^(@) + sin 6^(@) =

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