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If tanalpha=m/(m+1)a n dtanbeta=1/(2m+1)...

If `tanalpha=m/(m+1)a n dtanbeta=1/(2m+1)` . Find the possible values of `(alpha+beta)`

A

`pi //2`

B

`pi//3`

C

`pi//6`

D

`pi//4`

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The correct Answer is:
D
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