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Two stations due south of a leaning towe...

Two stations due south of a leaning tower which leans towards the north are respectively at distance x and y from its foot `(y gt x)`. If `alpha and beta` be the elevations of the top of the tower from these stations and `theta` is inclination of the tower to the horizontal then `cottheta` equals

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Two stations due south of a leaning tower which leans towards the north are at distances a and b from its foot If alpha and beta are the elevations of the top of the tower from these stations then prove that its inclination theta to the horizontal is given by cot theta=(b cot alpha-a cot beta)/(b-a)

Two stations due south of a leaning tower which leans towards the north are at distances a and b from its foot.If alpha beta be the elevations of the top of the tower from these stations, prove that its inclination theta to the horizontal is given by cot theta=(b cot alpha-a cot beta)/(b-a)

Knowledge Check

  • The respective ratio between the height of tower and the point at some distance from its foot is 5sqrt(3):5 .What will be the angle of elevation of the top of the tower ?

    A
    `30^(@)`
    B
    `60^(@)`
    C
    `90^(@)`
    D
    `45^(@)`

  • The angle of elevation of the top of a tower at a horizontal distance equal to the height of the tower from the base of the tower is

    A
    `30^(@)`
    B
    `45^(@)`
    C
    `60^(@)`
    D
    any acute angle

  • The angle of elevation of the top of a tower of height 100sqrt3 m from a point at a distance of 100 m from the foot of the tower on a horizontal plane is

    A
    `60^(@)`
    B
    `90^(@)`
    C
    `120^(@)`
    D
    `180^(@)`

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    From a point on the ground which is at a distance of 50 m from the foot of the towe, the angle of elevation of the top of the tower is observed to be 30^(@) . Find the height of the tower.

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