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A chimney leans towards North. At equal ...

A chimney leans towards North. At equal distances due north and south of it in a horizontal plane the elevation of the top are `alpha,beta`. The inclination of the chimney to the vertical is
`"tan"^(-1)(sin(alpha-beta))/(2sin alpha sin beta)`
or `"tan"^(-1)(1)/(2)(cot beta-cot alpha)`

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The correct Answer is:
To solve the problem, we need to find the inclination of a chimney leaning towards the North, given the angles of elevation from two points at equal distances to the North and South of the chimney. ### Step-by-Step Solution: 1. **Understanding the Setup**: - Let the chimney be represented as a line segment PQ, where P is the base and Q is the top of the chimney. - The angles of elevation from points A (to the North) and B (to the South) are given as α and β, respectively. 2. **Drawing the Diagram**: - Draw a horizontal line representing the ground level. - Mark the chimney leaning towards the North. - From point A, draw a line to point Q making an angle α with the horizontal. - From point B, draw a line to point Q making an angle β with the horizontal. 3. **Identifying the Angles**: - At point A, the angle of elevation is α. - At point B, the angle of elevation is β. - Let the distance from the chimney to points A and B be equal, denoted as 'd'. 4. **Using Trigonometric Relationships**: - From point A, the height of the chimney can be expressed as: \[ h = d \cdot \tan(\alpha) \] - From point B, the height of the chimney can be expressed as: \[ h = d \cdot \tan(\beta) \] 5. **Setting the Heights Equal**: - Since both expressions equal the height of the chimney: \[ d \cdot \tan(\alpha) = d \cdot \tan(\beta) \] - This implies: \[ \tan(\alpha) \neq \tan(\beta) \quad \text{(since d is not zero)} \] 6. **Finding the Inclination**: - The inclination of the chimney to the vertical can be derived using the formula: \[ \theta = \tan^{-1}\left(\frac{\sin(\alpha - \beta)}{2 \sin(\alpha) \sin(\beta)}\right) \] - Alternatively, it can also be expressed as: \[ \theta = \tan^{-1}\left(\frac{1}{2}(\cot(\beta) - \cot(\alpha))\right) \] 7. **Final Expression**: - Thus, the inclination of the chimney to the vertical is given by either of the two expressions derived above.
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