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Let f be a continuous function on [1,3] ...

Let f be a continuous function on [1,3] which takes rational values for all x. If f(2) =10 then f(2.5) is equal to:

A

25

B

20

C

`(f(1) + f(3))/2`

D

10

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the given information about the function \( f \). ### Step-by-Step Solution: 1. **Understanding the Function**: We are given that \( f \) is a continuous function on the interval \([1, 3]\) and takes rational values for all \( x \) in that interval. 2. **Given Value**: We know that \( f(2) = 10 \). 3. **Properties of Rational and Irrational Numbers**: Since \( f \) is continuous and takes rational values, we need to consider the implications of continuity. Between any two rational numbers, there exists an irrational number. If \( f \) were to take different rational values at different points, it would imply that there are irrational values in between, which would break the continuity of \( f \). 4. **Conclusion about the Function**: The only way for \( f \) to remain continuous and take only rational values is if \( f \) is a constant function. This means that \( f(x) = k \) for some rational number \( k \) for all \( x \) in \([1, 3]\). 5. **Finding the Constant Value**: Since we know \( f(2) = 10 \), we can conclude that \( k = 10 \). Therefore, the function must be \( f(x) = 10 \) for all \( x \) in the interval \([1, 3]\). 6. **Evaluating \( f(2.5) \)**: Since \( f(x) = 10 \) for all \( x \), we can directly find: \[ f(2.5) = 10 \] ### Final Answer: Thus, \( f(2.5) = 10 \). ---
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