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If f(x) be a continuous function and g(x...

If f(x) be a continuous function and g(x) be discontinuous function then f{x)+g (x) is a discontinuous function.

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To prove that \( f(x) + g(x) \) is a discontinuous function when \( f(x) \) is continuous and \( g(x) \) is discontinuous, we will analyze the definitions of continuity and discontinuity step by step. ### Step-by-Step Solution: 1. **Understanding Continuity**: A function \( f(x) \) is continuous at a point \( x = a \) if: - The left-hand limit \( \lim_{x \to a^-} f(x) \) exists. - The right-hand limit \( \lim_{x \to a^+} f(x) \) exists. - The value of the function at that point \( f(a) \) is equal to both limits: \[ \lim_{x \to a} f(x) = f(a) \] 2. **Understanding Discontinuity**: A function \( g(x) \) is discontinuous at a point \( x = a \) if at least one of the following conditions fails: - The left-hand limit \( \lim_{x \to a^-} g(x) \) exists. - The right-hand limit \( \lim_{x \to a^+} g(x) \) exists. - The value of the function at that point \( g(a) \) is equal to both limits. 3. **Setting Up the Problem**: Let \( f(x) \) be continuous at \( x = a \) and \( g(x) \) be discontinuous at \( x = a \). We denote: - \( \lim_{x \to a^-} f(x) = L_f \) - \( \lim_{x \to a^+} f(x) = L_f \) - \( f(a) = L_f \) For \( g(x) \): - Let \( \lim_{x \to a^-} g(x) = L_{g^-} \) - Let \( \lim_{x \to a^+} g(x) = L_{g^+} \) - \( g(a) \) may not equal either of these limits. 4. **Calculating Limits of the Sum**: We now consider the sum \( f(x) + g(x) \): - The left-hand limit of the sum as \( x \to a \): \[ \lim_{x \to a^-} (f(x) + g(x)) = \lim_{x \to a^-} f(x) + \lim_{x \to a^-} g(x) = L_f + L_{g^-} \] - The right-hand limit of the sum as \( x \to a \): \[ \lim_{x \to a^+} (f(x) + g(x)) = \lim_{x \to a^+} f(x) + \lim_{x \to a^+} g(x) = L_f + L_{g^+} \] 5. **Analyzing Continuity of the Sum**: For \( f(x) + g(x) \) to be continuous at \( x = a \), we need: \[ \lim_{x \to a^-} (f(x) + g(x)) = \lim_{x \to a^+} (f(x) + g(x)) = (f(a) + g(a)) \] This implies: \[ L_f + L_{g^-} = L_f + L_{g^+} = f(a) + g(a) \] 6. **Conclusion**: Since \( g(x) \) is discontinuous, \( L_{g^-} \neq L_{g^+} \). Therefore, \( L_f + L_{g^-} \neq L_f + L_{g^+} \). This means: \[ \lim_{x \to a^-} (f(x) + g(x)) \neq \lim_{x \to a^+} (f(x) + g(x)) \] Hence, \( f(x) + g(x) \) is discontinuous at \( x = a \).
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