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Let f: R to R be a positive increasing f...

Let `f: R to R` be a positive increasing function with `lim_(x to infty) (f(3x))/(f(x))=1`. Then `lim_(x to infty) (f(2x))/(f(x))` =

A

1

B

`2/3`

C

`3/2`

D

3

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The correct Answer is:
To solve the problem, we start with the given information: 1. \( f: \mathbb{R} \to \mathbb{R} \) is a positive increasing function. 2. We know that \( \lim_{x \to \infty} \frac{f(3x)}{f(x)} = 1 \). We need to find \( \lim_{x \to \infty} \frac{f(2x)}{f(x)} \). ### Step-by-step Solution: **Step 1: Understanding the limit condition** From the limit condition \( \lim_{x \to \infty} \frac{f(3x)}{f(x)} = 1 \), we can interpret that as \( f(3x) \) and \( f(x) \) becoming asymptotically equivalent as \( x \) approaches infinity. This suggests that the growth rates of \( f(3x) \) and \( f(x) \) are similar. **Hint for Step 1:** Consider what it means for two functions to be asymptotically equivalent as \( x \to \infty \). --- **Step 2: Using the property of increasing functions** Since \( f \) is an increasing function, we can say that for any \( c > 1 \): \[ \lim_{x \to \infty} \frac{f(cx)}{f(x)} = 1 \] This holds true for any constant \( c \) because as \( x \) becomes very large, the function's growth rate stabilizes. **Hint for Step 2:** Think about how increasing functions behave when scaled by a constant factor. --- **Step 3: Applying the limit to our specific case** Now, we can apply this property to our specific case where \( c = 2 \): \[ \lim_{x \to \infty} \frac{f(2x)}{f(x)} = 1 \] **Hint for Step 3:** Use the established property of limits for increasing functions to find the limit for \( c = 2 \). --- **Step 4: Conclusion** Thus, we conclude that: \[ \lim_{x \to \infty} \frac{f(2x)}{f(x)} = 1 \] This means that as \( x \) approaches infinity, the ratio of \( f(2x) \) to \( f(x) \) approaches 1, indicating that \( f(2x) \) and \( f(x) \) are asymptotically equivalent. **Final Answer:** \[ \lim_{x \to \infty} \frac{f(2x)}{f(x)} = 1 \] ---
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