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Let f : (-1,1) to R be a differentiabale...

Let f : (-1,1) `to` R be a differentiabale function with f(0) = -1 and f'(0) = 1. Let
g(x) = `[f(2f(x)+2)]^(2)` , then g'(0)=

A

4

B

`-4`

C

0

D

`-2`

Text Solution

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The correct Answer is:
B
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