Home
Class 12
MATHS
The height of the cylinder of max. volum...

The height of the cylinder of max. volume that can be inscribed in a sphere of radius a is

A

`(2a)/sqrt3`

B

`a/sqrt2`

C

`(5a)/4`

D

None

Text Solution

AI Generated Solution

The correct Answer is:
To find the height of the cylinder of maximum volume that can be inscribed in a sphere of radius \( a \), we can follow these steps: ### Step 1: Understand the Geometry We have a sphere of radius \( a \) and a cylinder inscribed within it. Let the radius of the cylinder be \( r \) and the height of the cylinder be \( h \). ### Step 2: Relate the Cylinder and Sphere The cylinder is inscribed in the sphere, which means that the diagonal of the cylinder (from the center of the base to the top edge) will equal the radius of the sphere. If we let the height of the cylinder be \( h \) and the radius of the cylinder be \( r \), we can use the Pythagorean theorem in the triangle formed by the radius of the sphere, the radius of the cylinder, and half the height of the cylinder: \[ a^2 = r^2 + \left(\frac{h}{2}\right)^2 \] ### Step 3: Express Volume of the Cylinder The volume \( V \) of the cylinder can be expressed as: \[ V = \pi r^2 h \] ### Step 4: Substitute for \( r \) From the Pythagorean theorem, we can express \( r^2 \) in terms of \( h \): \[ r^2 = a^2 - \left(\frac{h}{2}\right)^2 \] Substituting this into the volume formula gives: \[ V = \pi (a^2 - \left(\frac{h}{2}\right)^2) h \] ### Step 5: Simplify the Volume Expression Expanding this, we have: \[ V = \pi \left(a^2h - \frac{h^3}{4}\right) \] ### Step 6: Differentiate the Volume To find the maximum volume, we differentiate \( V \) with respect to \( h \): \[ \frac{dV}{dh} = \pi \left(a^2 - \frac{3h^2}{4}\right) \] ### Step 7: Set the Derivative to Zero Setting the derivative equal to zero to find critical points: \[ a^2 - \frac{3h^2}{4} = 0 \] Solving for \( h \): \[ \frac{3h^2}{4} = a^2 \implies h^2 = \frac{4a^2}{3} \implies h = \frac{2a}{\sqrt{3}} \] ### Step 8: Conclusion Thus, the height of the cylinder of maximum volume that can be inscribed in a sphere of radius \( a \) is: \[ h = \frac{2a}{\sqrt{3}} \]
Promotional Banner

Topper's Solved these Questions

  • MAXIMA AND MINIMA

    ML KHANNA|Exercise PROBLEM SET(3) (TRUE AND FALSE )|8 Videos
  • MAXIMA AND MINIMA

    ML KHANNA|Exercise PROBLEM SET(3) (FILL IN THE BLANKS )|8 Videos
  • MAXIMA AND MINIMA

    ML KHANNA|Exercise PROBLEM SET (2) (TRUE AND FALSE )|1 Videos
  • MATRICES

    ML KHANNA|Exercise COMPREHENSION|3 Videos
  • MEASURES OF CENTRAL TENDENCY

    ML KHANNA|Exercise ASSERTION / REASON|1 Videos

Similar Questions

Explore conceptually related problems

Show that the height of the cylinder of maximum volume that can be inscribed in a sphere of radius R is (2R)/(sqrt(3))

Show that the height of the cylinder of maximum volume that can be inscribed in a sphere of radius R is 2(R)/(sqrt(3)) .Also find maximum volume.

Show that the height of the cylinder of maximum volume that can be inscribed in a sphere of radius R is (2R)/(sqrt(3)) Also find the maximum volume.

The height of the cylinder of maximum volume which can be inscribed in a sphere of radius 3cm is

Show that the height of the cone of maximum volume that can be inscribed in a sphere of radius 12cm is 16cm.

Show that the height of the cone of maximum vvolume that can be inscribed in a sphere of radius 12cm is 16cm.

The height of the cylinder of the greatest volume that can be inscribed in a sphere of radius 3 is

Show that the height of the cylinder of maximum volume that can be inscribed in a cone of height h is (1)/(3)h

Show that the radius of right - circular cylinder of maximum volume, that can be inscribed in a sphere of radius 18 cm, is 6sqrt6cm .