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The solution of t the equation int(sqrt2...

The solution of `t` the equation `int_(sqrt2)^(t) (dx)/(xsqrt((x^2 - 1))) = pi/12` is

A

`2`

B

`sqrt(2)`

C

`2sqrt(3)`

D

`1`

Text Solution

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The correct Answer is:
To solve the equation \[ \int_{\sqrt{2}}^{t} \frac{dx}{x \sqrt{x^2 - 1}} = \frac{\pi}{12} \] we will follow these steps: ### Step 1: Identify the Integral The integral \[ \int \frac{dx}{x \sqrt{x^2 - 1}} \] is known to be \[ \sec^{-1}(x) + C \] where \( C \) is the constant of integration. ### Step 2: Apply the Limits of Integration Using the limits of integration from \(\sqrt{2}\) to \(t\), we can express the integral as: \[ \sec^{-1}(t) - \sec^{-1}(\sqrt{2}) = \frac{\pi}{12} \] ### Step 3: Calculate \(\sec^{-1}(\sqrt{2})\) We know that \[ \sec(\frac{\pi}{4}) = \sqrt{2} \] Thus, \[ \sec^{-1}(\sqrt{2}) = \frac{\pi}{4} \] ### Step 4: Substitute and Rearrange Substituting this value back into the equation gives: \[ \sec^{-1}(t) - \frac{\pi}{4} = \frac{\pi}{12} \] Adding \(\frac{\pi}{4}\) to both sides: \[ \sec^{-1}(t) = \frac{\pi}{4} + \frac{\pi}{12} \] ### Step 5: Find a Common Denominator To add these fractions, we find a common denominator. The least common multiple of 4 and 12 is 12: \[ \frac{\pi}{4} = \frac{3\pi}{12} \] Thus, \[ \sec^{-1}(t) = \frac{3\pi}{12} + \frac{\pi}{12} = \frac{4\pi}{12} = \frac{\pi}{3} \] ### Step 6: Solve for \(t\) Taking the secant of both sides: \[ t = \sec\left(\frac{\pi}{3}\right) \] We know that \[ \sec\left(\frac{\pi}{3}\right) = \frac{1}{\cos\left(\frac{\pi}{3}\right)} = \frac{1}{\frac{1}{2}} = 2 \] ### Final Answer Thus, the solution for \(t\) is: \[ \boxed{2} \]
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