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int (f(x) phi' (x) - f'(x) phi(x))/(f(x)...

`int (f(x) phi' (x) - f'(x) phi(x))/(f(x) . phi(x)) [log phi (x) - log f(x)] dx =`

A

`1/2 {log ((phi (x))/(f(x)))}^2`

B

`log(phi(x))/(f(x))`

C

`(phi(x))/(f(x)) "log" (phi(x))/(f(x))`

D

none

Text Solution

Verified by Experts

The correct Answer is:
A
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