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The value of int1^2 [f1 {f2 (x)}]^(-1) f...

The value of `int_1^2 [f_1 {f_2 (x)}]^(-1) f'_1 [f_2(x)] f'_2 (x) dx` where `f_2(1) = f_2(2)`, is equal to

A

0

B

1

C

2

D

none

Text Solution

Verified by Experts

The correct Answer is:
A
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