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int(cos 4x-1)/(cot x-tanx)dx is equal to...

`int(cos 4x-1)/(cot x-tanx)dx` is equal to

A

`-1/2 "cos" 4x + c`

B

`-1/4 "cos" 4x + c`

C

`-1/2 sin 2x + c`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
D
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