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(i) int 1/("sin"(x - a) "cos" (x - b)) d...

(i) `int 1/("sin"(x - a) "cos" (x - b)) dx`
(ii) `int 1/("cos" (x - a) "cos" (x - b)) dx`

A

`1/("cos" (a - b)) "log" (sin (x - a))/(cos (x -b))`

B

`1/("cos" (a - b)) "log" (sin (x - a))/(sin (x -b))`

C

`1/("sin" (a - b)) "log" (cos (x - a))/(cos (x -b))`

D

`1/("sin" (a - b)) "log" (sin (x - a))/(sin (x -b))`

Text Solution

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The correct Answer is:
A, C
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