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If un = int0^(pi//4) tan^n x dx then ...

If `u_n = int_0^(pi//4) tan^n x dx` then
`u_2 + u_4, u_3 + u_5, u_4 + u_6`..... are in

A

A.P.

B

G.P.

C

H.P.

D

None

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the sequence defined by \( u_n = \int_0^{\frac{\pi}{4}} \tan^n x \, dx \) and determine whether the sums \( u_2 + u_4, u_3 + u_5, u_4 + u_6, \ldots \) form an arithmetic progression (AP), geometric progression (GP), harmonic progression (HP), or none of these. ### Step 1: Finding \( u_n \) We start with the expression for \( u_n \): \[ u_n = \int_0^{\frac{\pi}{4}} \tan^n x \, dx \] Using integration by parts or a known result, we can derive a relationship between \( u_n \) and \( u_{n-2} \): \[ u_n + u_{n-2} = \frac{1}{n-1} \quad \text{for } n \geq 2 \] ### Step 2: Finding specific sums We will compute the sums \( u_2 + u_4, u_3 + u_5, u_4 + u_6 \) using the relationship we derived. 1. **For \( n = 4 \)**: \[ u_4 + u_2 = \frac{1}{4 - 1} = \frac{1}{3} \] 2. **For \( n = 5 \)**: \[ u_5 + u_3 = \frac{1}{5 - 1} = \frac{1}{4} \] 3. **For \( n = 6 \)**: \[ u_6 + u_4 = \frac{1}{6 - 1} = \frac{1}{5} \] ### Step 3: Analyzing the sums Now we have the following sums: - \( u_2 + u_4 = \frac{1}{3} \) - \( u_3 + u_5 = \frac{1}{4} \) - \( u_4 + u_6 = \frac{1}{5} \) ### Step 4: Checking for Progression To check if these sums form an arithmetic progression (AP), we need to check if the difference between consecutive terms is constant: - The difference between the first two sums: \[ \frac{1}{4} - \frac{1}{3} = \frac{3 - 4}{12} = -\frac{1}{12} \] - The difference between the second and third sums: \[ \frac{1}{5} - \frac{1}{4} = \frac{4 - 5}{20} = -\frac{1}{20} \] Since the differences are not equal, the sums do not form an AP. ### Step 5: Checking for Harmonic Progression (HP) To check if the sums form a harmonic progression, we need to check if the reciprocals of these sums are in arithmetic progression: - The reciprocals are: \[ 3, 4, 5 \] These numbers are in AP since: \[ 4 - 3 = 1 \quad \text{and} \quad 5 - 4 = 1 \] ### Conclusion Since the reciprocals of the sums \( u_2 + u_4, u_3 + u_5, u_4 + u_6 \) are in arithmetic progression, we conclude that the original sums are in harmonic progression (HP). Thus, the final answer is that \( u_2 + u_4, u_3 + u_5, u_4 + u_6, \ldots \) are in HP.
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