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The area bounded by y=cos x and x=-pi/2 ...

The area bounded by `y=cos x and x=-pi/2 and x=2pi`.and the axis of xin square units is

A

4

B

5

C

6

D

7

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The correct Answer is:
To find the area bounded by the curve \( y = \cos x \), the lines \( x = -\frac{\pi}{2} \) and \( x = 2\pi \), and the x-axis, we will follow these steps: ### Step 1: Set up the integral for the area The area \( A \) under the curve from \( x = a \) to \( x = b \) can be calculated using the integral: \[ A = \int_{a}^{b} y \, dx \] In this case, \( y = \cos x \), \( a = -\frac{\pi}{2} \), and \( b = 2\pi \). ### Step 2: Identify the intervals of integration The function \( \cos x \) oscillates between positive and negative values. We need to determine where \( \cos x \) is positive and negative within the interval \( [-\frac{\pi}{2}, 2\pi] \). 1. From \( x = -\frac{\pi}{2} \) to \( x = \frac{\pi}{2} \), \( \cos x \) is positive. 2. From \( x = \frac{\pi}{2} \) to \( x = \frac{3\pi}{2} \), \( \cos x \) is negative. 3. From \( x = \frac{3\pi}{2} \) to \( x = 2\pi \), \( \cos x \) is positive again. ### Step 3: Break the integral into parts We can break the integral into three parts based on the intervals identified: \[ A = \int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \cos x \, dx + \int_{\frac{\pi}{2}}^{\frac{3\pi}{2}} \cos x \, dx + \int_{\frac{3\pi}{2}}^{2\pi} \cos x \, dx \] ### Step 4: Calculate each integral 1. **First Integral**: \[ A_1 = \int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \cos x \, dx \] \[ = [\sin x]_{-\frac{\pi}{2}}^{\frac{\pi}{2}} = \sin\left(\frac{\pi}{2}\right) - \sin\left(-\frac{\pi}{2}\right) = 1 - (-1) = 2 \] 2. **Second Integral**: \[ A_2 = \int_{\frac{\pi}{2}}^{\frac{3\pi}{2}} \cos x \, dx \] \[ = [\sin x]_{\frac{\pi}{2}}^{\frac{3\pi}{2}} = \sin\left(\frac{3\pi}{2}\right) - \sin\left(\frac{\pi}{2}\right) = -1 - 1 = -2 \] Since area cannot be negative, we take the absolute value: \[ A_2 = 2 \] 3. **Third Integral**: \[ A_3 = \int_{\frac{3\pi}{2}}^{2\pi} \cos x \, dx \] \[ = [\sin x]_{\frac{3\pi}{2}}^{2\pi} = \sin(2\pi) - \sin\left(\frac{3\pi}{2}\right) = 0 - (-1) = 1 \] ### Step 5: Sum the areas Now, we can sum the areas from each part: \[ A = A_1 + |A_2| + A_3 = 2 + 2 + 1 = 5 \] ### Final Answer The area bounded by the curve \( y = \cos x \), the lines \( x = -\frac{\pi}{2} \) and \( x = 2\pi \), and the x-axis is: \[ \boxed{5} \text{ square units} \]
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ML KHANNA-AREA OF CURVES-SELF ASSESSEMENT TEST
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