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Solution of the differential equation ...

Solution of the differential equation
`sin2x (dy)/(dx) -y=tan x` is

A

`y=tan x +c sqrt(tan x)`

B

`x-y sin x=c`

C

`xy tan x =c`

D

none of these

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The correct Answer is:
To solve the differential equation \( \sin(2x) \frac{dy}{dx} - y = \tan(x) \), we will follow these steps: ### Step 1: Rearranging the Equation First, we rearrange the equation to isolate \( \frac{dy}{dx} \): \[ \sin(2x) \frac{dy}{dx} = y + \tan(x) \] Now, divide both sides by \( \sin(2x) \): \[ \frac{dy}{dx} = \frac{y}{\sin(2x)} + \frac{\tan(x)}{\sin(2x)} \] ### Step 2: Identify the Standard Form The equation can be rewritten in the standard form of a linear differential equation: \[ \frac{dy}{dx} + P(x) y = Q(x) \] where \( P(x) = -\frac{1}{\sin(2x)} \) and \( Q(x) = \frac{\tan(x)}{\sin(2x)} \). ### Step 3: Finding the Integrating Factor The integrating factor \( \mu(x) \) is given by: \[ \mu(x) = e^{\int P(x) \, dx} = e^{\int -\frac{1}{\sin(2x)} \, dx} \] To compute this integral, we can use the identity \( \sin(2x) = 2 \sin(x) \cos(x) \): \[ \int -\frac{1}{\sin(2x)} \, dx = -\frac{1}{2} \int \left( \frac{1}{\sin(x)} + \frac{1}{\cos(x)} \right) \, dx \] This integral can be computed, leading to: \[ \mu(x) = e^{-\frac{1}{2} \log(\sin(2x))} = \frac{1}{\sqrt{\sin(2x)}} \] ### Step 4: Multiply the Equation by the Integrating Factor Now, we multiply the entire differential equation by the integrating factor: \[ \frac{1}{\sqrt{\sin(2x)}} \frac{dy}{dx} - \frac{y}{\sin(2x)^{3/2}} = \frac{\tan(x)}{\sin(2x)^{3/2}} \] ### Step 5: Solve the Left Side The left-hand side can be expressed as: \[ \frac{d}{dx} \left( y \cdot \frac{1}{\sqrt{\sin(2x)}} \right) \] Thus, we have: \[ \frac{d}{dx} \left( y \cdot \frac{1}{\sqrt{\sin(2x)}} \right) = \frac{\tan(x)}{\sin(2x)^{3/2}} \] ### Step 6: Integrate Both Sides Integrating both sides gives: \[ y \cdot \frac{1}{\sqrt{\sin(2x)}} = \int \frac{\tan(x)}{\sin(2x)^{3/2}} \, dx + C \] ### Step 7: Solve for y Finally, we solve for \( y \): \[ y = \sqrt{\sin(2x)} \left( \int \frac{\tan(x)}{\sin(2x)^{3/2}} \, dx + C \right) \] ### Final Solution The final solution to the differential equation is: \[ y = \sqrt{\sin(2x)} \left( \int \frac{\tan(x)}{\sin(2x)^{3/2}} \, dx + C \right) \]
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ML KHANNA-DIFFERENTIAL EQUATIONS-Problem Set (2) (MULTIPLE CHOICE QUESTIONS)
  1. Solution of the differential equation (dy)/(dx) +y cot x =2 cos x ...

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  2. Solution of the differential equation (1+y^(2))dx =(tan^(-1)y-x)dy...

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  3. Solution of the differential equation (1+x^(2)) (dy)/(dx)+y=tan^(-1)x...

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  4. Solution of the differential equation 2y sin x (dy//dx)=2 sin x cos ...

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  5. The Solution of the equation (dy)/(dx)+2y=sin x is

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  6. The Solution of the equation (dy)/(dx)+y tan x =sec x is

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  7. The Solution of the equation x log x (dy)/(dx) +y = 2 log x is

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  8. Solution of the differential equation x(dy)/(dx)+2y=x^(2)logx is

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  9. The Solution of the equation (1+x^(2)) (dy)/(dx)+2xy -4x^(2)=0

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  10. The solution of differential equation (dy)/(dx)-3y= sin 2x is

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  11. The solution of the equation (dy)/(dx)+3y=cos^(2)x is

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  12. The gradient of the curve passing through (4,0) is given by (dy)/(dx) ...

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  13. Solution of the differential equation sin2x (dy)/(dx) -y=tan x is

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  14. The Solution of the differential equation (dy)/(dx) +(1)/(x)tan y =(1...

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  15. Solution of the equation (dy)/(dx) = e^(x-y) (e^(x)-e^(y)) is equal t...

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  16. If y(t) is solution of (t+1)(dy)/(dt) -ty =1, y(0)= -1. At t = 1 the s...

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  17. The solution of differential equation (dy)/(dx)(x^(2)y^(3)+xy) =1 is...

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  18. The solution of the differential equation (dy)/(dx)-(x log x)/(1+log...

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  19. If (dy)/(dx)+Py=Q where P and Q are functions of x alone then integrat...

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  20. Let f(x) be differentiable on the interval (0,oo) such that f(1)=1 and...

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