5-Bromo-2-cyclopropyl cyclohex-2-enol have correct structure is:

Options

A.
B.
C.
D.

Explanation

To determine the correct structure of 5-Bromo-2-cyclopropyl-cyclohex-2-enol, we will follow these steps:

### Step 1: Identify the components of the name
The name "5-Bromo-2-cyclopropyl-cyclohex-2-enol" indicates the following:
- **5-Bromo**: There is a bromine (Br) substituent at the 5th position.
- **2-Cyclopropyl**: There is a cyclopropyl group at the 2nd position.
- **Cyclohex-2-enol**: The base structure is cyclohexene with an alcohol (OH) group at the 2nd position.

### Step 2: Draw the base structure
Start by drawing the cyclohexene ring. Cyclohexene has a double bond, so we will include that in the structure.

### Step 3: Number the carbon atoms
Number the carbon atoms in the cyclohexene ring starting from the carbon that is part of the double bond (the one closest to the alcohol group). The numbering should be done in such a way that the substituents get the lowest possible numbers:
- Assign the double bond to carbons 1 and 2.
- Number the rest of the ring accordingly.

### Step 4: Place the substituents
- At position 2, add the cyclopropyl group.
- At position 5, add the bromine atom.
- At position 2 (the same as the double bond), add the hydroxyl (OH) group.

### Step 5: Verify the structure
Check if the structure matches the name:
- The cyclopropyl group should be at position 2.
- The bromine should be at position 5.
- The double bond should be between carbons 1 and 2, with the hydroxyl group also at position 2.

### Final Structure
The final structure should look like this:
```
Br
|
C1=C2-OH
/ \
C6 C3
| |
C5 C4
```
Where C1 and C2 are part of the double bond, C2 has the OH group, C2 has the cyclopropyl group, and Br is at C5.