The reaction of toluene with chlorine in the presence of light gives :

Options

A.
B.
C.
D.

Explanation

To solve the question regarding the reaction of toluene with chlorine in the presence of light, we can follow these steps:

### Step 1: Identify the Reactants
- The reactants in this reaction are toluene (C6H5CH3) and chlorine (Cl2).

### Step 2: Understand the Reaction Conditions
- The reaction occurs in the presence of light (denoted as Hν), which indicates that this is a photochemical reaction. This condition typically leads to a free radical mechanism.

### Step 3: Mechanism of the Reaction
- In the presence of light, chlorine molecules (Cl2) can dissociate into two chlorine radicals (Cl•).
- The chlorine radicals can then react with toluene, which has a methyl group (–CH3) attached to the benzene ring.

### Step 4: Formation of Benzyl Radical
- The chlorine radical abstracts a hydrogen atom from the methyl group of toluene, forming a benzyl radical (C6H5CH2•).

### Step 5: Formation of Benzyl Chloride
- The benzyl radical can then react with another chlorine molecule (Cl2) to form benzyl chloride (C6H5CH2Cl) and regenerate a chlorine radical.
- The overall reaction can be summarized as:
\[ C6H5CH3 + Cl2 \xrightarrow{h\nu} C6H5CH2Cl + HCl \]

### Step 6: Conclusion
- The product of the reaction of toluene with chlorine in the presence of light is benzyl chloride (C6H5CH2Cl).

### Final Answer
- The correct answer is benzyl chloride.

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