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If a person uses spectacles of power + 1...

If a person uses spectacles of power + 1.0 dioptre, what is the nearest distance of distinct vision for him ? Given that near point of the person is 75 cm from the eye.

Text Solution

Verified by Experts

`P=1D`
`P=(1)/(f("in m"))`
`rArr f=(1)/(P)=(1)/(1)=1m=100cm`
Distance of near point = x = 75 cm
Focal length of corrective lens is given by
`f=(xD)/(x-D)`
`100=(75D)/(75-D)`
`7500-100D=75D`
`100D+75D=7500`
`175D=7500`
`D=(7500)/(175)=42.86cm`
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