Home
Class 12
PHYSICS
Find out binding energy and binding ener...

Find out binding energy and binding energy per nucleon of `"_3Li^7` nucleus. Given mass of proton = 1.00782 amu mass of a neutron = 1.00866 amu and mass of "_3Li^7` `"_3(Lithium)^7` nucleus = 7.01599 amu.

Text Solution

Verified by Experts

Mass of Lithium (Li) nucleus = `M_(N)` = 7.01599 amu
Mass of proton = `m_(p)` =1-00782 amu
Mass of neutron = `m_(n)` =1.00866 amu
In Lithium nucleus, there are three protons and four neutrons.
`therefore`
`=3xx 1·00782 +4 xx 1-00866-7.01599`
`=3.02346 +4.03464-7.01599 =7.0581-7.01599`
=0.0421 amu
Binding energy =`triangle m xx 931.5 MeV`
=0.042111 `xx` 931.5
=39.23 MeV
Binding energy per nucleon
`("B.E")/(A ("Atomic Number"))`
= 5.60 MeV/nucleon.
Promotional Banner

Topper's Solved these Questions

  • STRUCTURE OF NUCLEUS

    BETTER CHOICE PUBLICATION|Exercise MOST EXPECTED QUESTIONS |4 Videos

  • STRUCTURE OF NUCLEUS

    BETTER CHOICE PUBLICATION|Exercise LONG ANSWER TYPE QUESTIONS|1 Videos

  • SEMI CONDUCTOR DEVICES

    BETTER CHOICE PUBLICATION|Exercise Most Expected Questions|6 Videos

  • WAVE NATURE OF MATER

    BETTER CHOICE PUBLICATION|Exercise Numerical Problems|21 Videos

Similar Questions

Explore conceptually related problems

Calculate mass defect, binding energy and binding energy per nucleon of deuteron ( "_1H^2 ) nucleus. Given mass of proton=1.007275 a.m.u., mass of neutron = 1.008665 a.m.u. and mass of deuteron =2.013553 a.m.u.

Calculate the binding energy per nucleon of "_3Li^7 nucleus. Given mass of "_3Li^7 nucleus = 7.01599 a.m.u., mass of proton =1.007825 a.m.u., mass of neutron = 1.008665 a.m.u. and 1 a.m.u. = 931.5 MeV

Find binding energy per nucleon for helium nuclei. Given that mass of helium nucleus = 4.001509 amu, mass of proton=1.007277 amu and mass of neutron = 1.0086666 amu.