Concentrated `H_(2)SO_(4)` has a density 1 . 9 g/mL and is ` 99% H_(2) SO_(4)` by mass. Calculate the molarity of the acid

Answer

19.2 M

Explanation

Let ,Mass Of `99%` solution = 100 g
Mol . mass of `H_(2) SO_(4) = 98 g mol^(-1)`
`n_(H_(2)SO_(4)) = (99g)/( 98 g mol^(-1)) = 1 . 01 ` mol
vol. of solution ` = ("Mass of soution ")/( "Density f of solution ")`
`= (100 g)/( 1 . 9 g mL^(-1)) = 52 . 63 mL`
= 0 . 05263L
Molarity `= (n_(H_(2)SO_(4))) /("Vol. of solution ") = (1 . 01 mol)/( 0 . 05263)`
`= (101)/( 5 . 263) mol L^(-1)` = 19.19 M