Commercially available HCl contains 38% HCl by mass. Calculate molarity of solution if the density is 1.19 g/mol.

Answer

12.39 M

Explanation

Let mass of `30%` HCI solution = 100 g
`:.` Mass of HCI = 38 G
`= ("Mass of solution")/( "Density of solution")`
`= (100 g)/( 1. 19 g mL^(-)) = 84 . 034 mL`
` = 0 . 0 84 034 L ~~ 0 . 0 84 L`
Moles of solute, (HCI) ` = (38 g)/( 36 . 5 g mol^(-1))`
= 1.04 mol
(Molar mass of HCI `= 1 + 35 . 5 = 36 . 5 g mol^(-1)`)
Molarity `= ("Mole of solute ")/( "Volume of solution ")`
` = (1 . 0 4 mol)/( 0 . 084 L) = 12 . 38 mol L^(-1)`
= 12.39 M