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Calculate the molal elevation constant o...

Calculate the molal elevation constant of water `(K_(b) = ?)` . Given that 0 . 1 molar aquous solution of a substance boiled at `100 .052^(@)` C

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The correct Answer is:
`K_(b) = 0.52 K m^(-1)`
`m =0.1 m , Delta T_(b) = T_(b) - T_(b)^(0)`
`= (100 .052 - 100 )^(@) C `
`= 0.052^(@) C = 0.052 K`
`K_(b) = ?`
`Delta T_(b) = K_(b) xx m`
`K_(b) = (Delta T_(b))/(m)`
`= (0.052 K)/(0.1 m) = 0.52 Km^(-1)`
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