Boiling point of benzene is 353.23 K . When 1 . 80 g of non-volatile solute was dissolved in 90 g of benzene the boiling point is raised to 354. 11 K? Calculate molar mass of solute .
(`K_(b)` for benzene is 2 . 53 K kg ` mol^(-1)`)

The boiling point of benzene is 353.23 K. When 1.80g of a non-volatile solute was dissolved in 90 g of benzene, the boiling point is raised to 354.11 K. Calculate the molar mass of the solute.

The boiling point of Benzene (C_(6) H_(6)) is 353.23 K. When 1 . 80 g of a non - volatile solute was dissolved in 90 g of C_(6) H_(6) the boiling point is raised to 354 . 11 K. Calculate the molar mass of solute . (Given K_(b) for benzene is 2 . 53 K kg mol^(-1) )

10g of non-volatile solute when dissolved in 100g of benzene raises its boiling point by 1^@ C. What is the molecular mass of the solute. ( k_b for benzene=2.53 K kg mol^-1 )

A solution containing 12.5 g of a non- electrolyte substance in 175 g of water gave boiling point elevation of 0.70 K. Calculate the molar mass of the substance ( K_b for water = 0.52 K kg mol^(-) ).

3.0 g of non-volatile solute when dissolve in 1 litre water, shows an osmotic pressure of 2 atmosphere at 300 K. Calculate the molar mass of the solute. (R = 0.0821 litre atm K^(-1)"mol"^(-1) ).

15 g of an unknown molecular substance was dissolved in 450 g of water. The resulting solution freezes at - 0 . 34^(@) C . What is them molar ass of the substance ? ( K_(f) for water = 1. 86 K kg mol^(-1) )

1.5 g of a non-volatile non-electrolyte is dissolved in 50 g of benzene (K_b=2.5K kg mol^-1) . The elevation of boiling point of the solution is 0.75K. The molecular weigth of the solute is gmol^-1 is

On dissolving 0.25 g of a non-volatile substance in 30 mL of benzene (density 0.8 g "mol"^(-1) ) its freezing point decreases by 0.40^(@)C . Calculate the molecular mass of the non-volatile substance. ( K_(f) for benzene is 5.12 k m^(-1) )