If `0ltxltpi and cosx +sinx = 1/2` then `tan x` is (A) `(-(4+sqrt(7))/3)` (B) (1+sqrt(7))/4` (C) `(1-sqrt(7))/4` (D) `(4+sqrt(7))/3`

If 0ltxltpi and cosx + sinx =1/2 , then tanx is (1) (4-sqrt(7))/3 (2) -(4+sqrt(7))/3 ( 3) (1+sqrt(7))/4 (4) (1-sqrt(7))/4

If sinx+cosx=(sqrt(7))/2, where x in 1s t quadrant, then tanx/2 is equal to (a) (3-sqrt(7))/3 (b) (sqrt(7)-2)/3 (c) (4-sqrt(7))/4 (d) none of these

If tangents P Q and P R are drawn from a point on the circle x^2+y^2=25 to the ellipse (x^2)/16+(y^2)/(b^2)=1,(b (a) (sqrt(5))/4 (b) (sqrt(7))/4 (c) (sqrt(7))/2 (d) (sqrt(5))/3

(sqrt(7)+2sqrt(3))(sqrt(7)-2sqrt(3))

Tangent of acute angle between the curves y=|x^2-1| and y=sqrt(7-x^2) at their points of intersection is (a) (5sqrt(3))/2 (b) (3sqrt(5))/2 (5sqrt(3))/4 (d) (3sqrt(5))/4

Prove that (1)/(sqrt(7))=(1)/(sqrt(7))times(sqrt(7))/(sqrt(7))

Tangent of acute angle between the curves y=|x^2-1| and y=sqrt(7-x^2) at their points of intersection is (5sqrt(3))/2 (b) (3sqrt(5))/2 (5sqrt(3))/4 (d) (3sqrt(5))/4

AB is a vertical pole with B at the ground level and A at the top. A man finds that the angle of elevation of the point A from a certain point C on the ground is 60o . He moves away from the pole along the line BC to a point D such that C D""=""7""m . From D the angle of elevation of the point A is 45o . Then the height of the pole is (1) (7sqrt(3))/2 1/(sqrt(3)-1)m (2) (7sqrt(3))/2 sqrt(3)+1m (3) (7sqrt(3))/2 sqrt(3)-1m (4) (7sqrt(3))/2 sqrt(3)+1m

1/(sqrt(7)+sqrt(3))\times (sqrt(7)-sqrt(3))/(sqrt(7)-sqrt(3))

The distance of the point P(1,-3) from the line 2y-3x=4 is (A) 13 (B) (7)/(13)sqrt(3) (C) sqrt(13) (D) (7)/(13)